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IrinaVladis [17]
2 years ago
12

You are asked to make a list of possible 5-character passwords using the first 7 letters of the alphabet. How many distinct pass

words can you make? Indicate whether this is a combination or permutation.
Mathematics
1 answer:
kakasveta [241]2 years ago
6 0

Using the permutation formula, as the order is important, it is found that 2520 distinct passwords can be made.

The order is important as abcde is a different password than edcba, hence the <em>permutation formula</em> is used.

<h3>What is the permutation formula?</h3>

The number of possible permutations of x elements from a set of n elements is given by:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this problem, 5 letters are chosen from a set of 7, hence:

P_{7,5} = \frac{7!}{(7-5)!} = 2520

2520 distinct passwords can be made.

More can be learned about the permutation formula at brainly.com/question/25925367

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The partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

<h3>How to determine the decomposition?</h3>

The fraction is given as:

\frac{8x + 19}{(x + 8)(x - 1)}

Split the fraction as follows:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}

Take the LCM

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{Ax -A + Bx + 8B}{(x + 8)(x -1)}

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\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Hence, the partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

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