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IrinaVladis [17]
2 years ago
12

You are asked to make a list of possible 5-character passwords using the first 7 letters of the alphabet. How many distinct pass

words can you make? Indicate whether this is a combination or permutation.
Mathematics
1 answer:
kakasveta [241]2 years ago
6 0

Using the permutation formula, as the order is important, it is found that 2520 distinct passwords can be made.

The order is important as abcde is a different password than edcba, hence the <em>permutation formula</em> is used.

<h3>What is the permutation formula?</h3>

The number of possible permutations of x elements from a set of n elements is given by:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this problem, 5 letters are chosen from a set of 7, hence:

P_{7,5} = \frac{7!}{(7-5)!} = 2520

2520 distinct passwords can be made.

More can be learned about the permutation formula at brainly.com/question/25925367

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7 0
2 years ago
Prove that (4n+1)^2(4n-1)^2 is a multiple of 8 for all integers of n.<br><br> thanks.
azamat

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(4n + 1)²(4n - 1)²

= [(4n + 1)(4n - 1)]²

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can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8

=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.

Step-by-step explanation:

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Answer:

True

Step-by-step explanation:

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