Using the permutation formula, as the order is important, it is found that 2520 distinct passwords can be made.
The order is important as abcde is a different password than edcba, hence the <em>permutation formula</em> is used.
<h3>What is the permutation formula?</h3>
The number of possible permutations of x elements from a set of n elements is given by:
![P_{(n,x)} = \frac{n!}{(n-x)!}](https://tex.z-dn.net/?f=P_%7B%28n%2Cx%29%7D%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-x%29%21%7D)
In this problem, 5 letters are chosen from a set of 7, hence:
![P_{7,5} = \frac{7!}{(7-5)!} = 2520](https://tex.z-dn.net/?f=P_%7B7%2C5%7D%20%3D%20%5Cfrac%7B7%21%7D%7B%287-5%29%21%7D%20%3D%202520)
2520 distinct passwords can be made.
More can be learned about the permutation formula at brainly.com/question/25925367