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IrinaVladis [17]
2 years ago
12

You are asked to make a list of possible 5-character passwords using the first 7 letters of the alphabet. How many distinct pass

words can you make? Indicate whether this is a combination or permutation.
Mathematics
1 answer:
kakasveta [241]2 years ago
6 0

Using the permutation formula, as the order is important, it is found that 2520 distinct passwords can be made.

The order is important as abcde is a different password than edcba, hence the <em>permutation formula</em> is used.

<h3>What is the permutation formula?</h3>

The number of possible permutations of x elements from a set of n elements is given by:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this problem, 5 letters are chosen from a set of 7, hence:

P_{7,5} = \frac{7!}{(7-5)!} = 2520

2520 distinct passwords can be made.

More can be learned about the permutation formula at brainly.com/question/25925367

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if you were supposed t solve for something else just comment and i'll come back :)

(next time state what ur solving for)

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