7x^4 + x^3 – 3x^2 + 5x – 2
basically you would do length x width
5x and x
6 and 4
What is the interquartile range of the data? 24, 25, 27, 36, 37, 42, 42, 43, 49, 49, 50, 53, 59, 61, 65 41 7 17 10
AysviL [449]
<span>The interquartile range is the difference between the third quartile and the first quartile. First, find the median so you can separate the data in half. The median is the middle number. Arrange the numbers from least to greatest and find the number in the middle.
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Find the medians of these two halves. These will be Quartile 1 and Quartile 3.

Quartile 1 is 36

Quartile 3 is 53
Answer:
912.
Step-by-step explanation:
Answer:
C: y=11x
Step-by-step explanation:
11x2=22
11x3=33
11x4=44
So on and so forth.