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g100num [7]
3 years ago
5

K is between P and Q. Suppose PQ- 10x - 16, PK - 6x + 8, and KQ-8. What is PQ?

Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

PQ = 64

Step-by-step explanation:

PQ = PK + KQ

10x - 16 = 6x + 8 + 8

10x - 16 = 6x + 16

4x = 32

x = 8

PQ = 10(8) - 16

     = 80 - 16

     = 64

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Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
Nutka1998 [239]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
Read 2 more answers
What is it !, help !
Gala2k [10]

Answer:

an isosceles triangle

Step-by-step explanation:

it has two equal sides so this is isosceles triangle

7 0
3 years ago
A store is having a 20% off sale on all merchandise. If Mai buys one item and saves 13$, what was the original sale price of her
Montano1993 [528]

Answer:

$65 is the original price

Step-by-step explanation:

65 x .8 = 52 which is 13 off

4 0
3 years ago
What is the sixth term in the geometric sequence described by this explicit formula? an=-5*(4)^(n-1)
Dmitrij [34]

Answer:

-5120

Step-by-step explanation:

Replace the n in the formula by 6.

a6 = -5(4)^(6-1)

= -5 * 4^5

= -5120

6 0
3 years ago
Read 2 more answers
A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?
Fynjy0 [20]

Answer:

The equation showing this situation is  D=b^2-4ac=0

Step-by-step explanation:

Given : A quadratic equation of the form ax^2 + bx + c=0  has one real number solution.

To find : Which could be the equation?  

Solution :

A quadratic equation in form ax^2+bx+c=0 has a solution x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} called a quadratic formula  in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

1) If D=b^2-4ac>0 there are two real roots.

2) If D=b^2-4ac=0 there are one real roots.

3) If D=b^2-4ac there are no real roots.

According to question,

A quadratic equation of the form ax^2 + bx + c=0  has one real number solution.

So, The equation showing this situation is  D=b^2-4ac=0

6 0
3 years ago
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