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g100num [7]
3 years ago
5

K is between P and Q. Suppose PQ- 10x - 16, PK - 6x + 8, and KQ-8. What is PQ?

Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

PQ = 64

Step-by-step explanation:

PQ = PK + KQ

10x - 16 = 6x + 8 + 8

10x - 16 = 6x + 16

4x = 32

x = 8

PQ = 10(8) - 16

     = 80 - 16

     = 64

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Calculate the Laplace transforms of the following from the definition. 1. y = t^2. y = t^3
Likurg_2 [28]

Answer:

1) L(y)=\frac{2}{s^{3}}

2) L(y)=\frac{6}{s^{4}}

Step-by-step explanation:

To find : Calculate the Laplace transforms of the following from the definition ?

Solution :

We know that,

Laplace transforms of t^n is given by,

L(t^n)=\frac{n!}{s^{n+1}}

1) y=t^2

Laplace of y,

L(y)=L(t^2) here n=2

L(y)=\frac{2!}{s^{2+1}}

L(y)=\frac{2}{s^{3}}

2) y=t^3

Laplace of y,

L(y)=L(t^3) here n=3

L(y)=\frac{3!}{s^{3+1}}

L(y)=\frac{3\times 2}{s^{4}}

L(y)=\frac{6}{s^{4}}

5 0
2 years ago
An open rectangular box with square base has a volume of 256 cubic inches. determine the equation for the volume and surface are
Serjik [45]
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box

we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1

surface area of the box=area of the base+perimeter of base*height

area of the base=b²
perimeter of the base=4*b

surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2

substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b

the answer is

the formula of the volume of the box is  V=b²*h-----> 256=b²*h

the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
4 0
3 years ago
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melomori [17]

Answer:

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Marco can swim at a speed of 45
diamong [38]
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4 0
2 years ago
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Solve for s.<br> 0.5s +1= 7+ 4.58<br> S =?
Lana71 [14]

Answer:

s = 21.16

Step-by-step explanation:

0.5s +1= 7+ 4.58

Combine like terms

0.5s +1=11.58

Subtract 1 from each side

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Multiply by 2

.5s *2 = 10.58*2

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4 0
2 years ago
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