The 9th and the 12th term of an arithmetic progression are 50 and 65 respectively. find the common difference
1 answer:
The first term of the arithmetic progression exists at 10 and the common difference is 2.
<h3>How to estimate the common difference of an arithmetic progression?</h3>
let the nth term be named x, and the value of the term y, then there exists a function y = ax + b this formula exists also utilized for straight lines.
We just require a and b. we already got two data points. we can just plug the known x/y pairs into the formula
The 9th and the 12th term of an arithmetic progression exist at 50 and 65 respectively.
9th term = 50
a + 8d = 50 ...............(1)
12th term = 65
a + 11d = 65 ...............(2)
subtract them, (2) - (1), we get
3d = 15
d = 5
If a + 8d = 50 then substitute the value of d = 5, we get
a + 8 5 = 50
a + 40 = 50
a = 50 - 40
a = 10.
Therefore, the first term is 10 and the common difference is 2.
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Function and its inverse was graphed.
<u>Step-by-step explanation:</u>
y = -4x²- 2
To find the inverse function of y = -4x²- 2 we have to transform the formula to calculate x in terms of y.
y = -4x²- 2
-4x² = y - 2
x = √(y-2) / -4
Now we can change the letters to follow the convention that x is the independent variable and y is the function's value:
y = √(x-2) / -4
Now we have to draw the graph as,
It was side by side that is LHS is the function and the RHS is its inverse.
