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3 years ago

CAN SOMEONE JUST PLEASE ANSWER THIS ASAP FOR BRAINLIEST!!!!

Mathematics

1 answer:

Sergio [31]3 years ago

6 0

I think the answer is 25

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The ratio of the lengths of corresponding sides of similar triangles is 3/8. What is the ratio (smaller to larger) of the areas?

svlad2 [7]

Answer:

9/64

Step-by-step explanation:

For similar triangles, the ratio of areas is the square of the ratio of corresponding sides.

The ratio of areas is (3/8)² = 9/64.

4 0

1 year ago

Help me with 16,17,18,and 19 please simpl

mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

$\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\ \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\ \\=\dfrac{t^2-4t-3}{t^2+3t+18}$

Ques 17)

$\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\ \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}$

Ques 18)

Let the blank space be denoted by the quantity 'x'.

$\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2$

Ques 19)

Let the missing quantity be denoted by 'x'.

$\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9$

7 0

2 years ago

5a+5b=25 and -5a+5b=35

Alex_Xolod [135]

add the two equations together

5a+5b=25

-5a+5b=35

------------------

0 + 10b =60

divide by 10

b=6

5a + 5b = 25

5a +5(6) = 25

5a +30 =25

subtract 30 from each side

5a =-5

divide by 5

a = -1

Answer (-1,6)

or a=-1 b=6

3 0

2 years ago

Can anyone figure this out

sergey [27]

Answer:

I know it.

Step-by-step explanation:

triangles always add up to 180 degrees so add 43 and 32 together and you will get 75 so then you take 75 off 180 and you will get 105

that's your answer

A = 105

7 0

2 years ago

Find f^-1(x) and it’s domain.

Mrac [35]

Answer: A

Step-by-step explanation:

Letting $f(y)=x$ ,

$x=\sqrt{y}-5\\\\x+5=\sqrt{y}\\\\y=(x+5)^{2}$

Also, the domain of an inverse is the same as the range of the original function, so the range is $x \geq 0$

7 0

1 year ago