Somebody help me please (10th grade geometry)
1 answer:
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Given parameters:
Length of earring hook = 1.5cm
Length of given wire = 45cm
Dimension of the triangle = 3.2cm, 3.2cm and 2.1cm
Unknown:
Number of earrings that can be made from the wire = ?
To solve this problem, we need to calculate the total length of the earring we want to make.
Total earring length = Perimeter of earring + length of earring hook
= 3.2 + 3.2 + 2.1 + 1.5
= 10cm
Now the length of the wire is 45cm,
Number of earrings = = 4.5 earrings
But this is not reasonable, therefore, we can only forge 4 complete earrings from the given length with 5cm of wire remaining.
The number of earrings that can be made is 4.
Answer:
x = 2
Step-by-step explanation:
The relevant rule of logarithms is ...
log(a/b) = log(a) -log(b)
This lets us combine the logs on the left to get ...
log((6 +7x)/(3x -2)) = log(5)
Taking anti-logs gives ...
(6 +7x)/(3x -2) = 5
6 +7x = 5(3x -2) . . . . . multiply by (3x -2)
7x +6 = 15x -10 . . . . . eliminate parentheses
8x = 16 . . . . . . . . . . . add 10-7x to both sides
x = 2 . . . . . . . . . . . . . divide by 8
The solution is x = 2.
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The graph shows the left side of the equation is equal to the right side for x=2.
