<span>4:12 or 1:3
20 character jump lol
kwapwao dpw</span>
It would be c I think: the problem says 2 divided by five and all the others are 5 divided by two
Answer:
18 muffins
Step-by-step explanation:
From the information given, you can write the following equations:
x+y=34 (1)
0.50x+0.75y=21 (2)
where x is the number of muffins and y is the number of bagels.
First, you can isolate x in (1):
x=34-y (3)
Then, you can replace (3) in (2):
0.50(34-y)+0.75y=21
17-0.5y+0.75y=21
0.25y=21-17
0.25y=4
y=4/0.25
y=16
Now you can replace the value of "y" in (3):
x=34-16
x=18
According to this, the answer is that you sold 18 muffins.
Almost 60 years after taking my last math class, I discovered
how to turn a repeating decimal into its equivalent fraction.
-- Take the set of digits that repeats, no matter how many digits there are.
Write them as the numerator of a fraction.
-- For the denominator, write the same number of '9's.
-- If it's possible and you feel like it, simplify (reduce) the fraction.
You have 0.023 with the 23 (two digits) repeating forever.
-- Write the 23 (two digits) as the numerator.
-- Write 99 (two digits) as the denominator.
Now you have the fraction 23 / 99 . It can't be reduced.
You actually had 0.0... before the repeating part. That just
means that the fraction has been divided by 10. The real
equivalent fraction is 23 / 990 . (Which also can't be reduced.)
After so many years not knowing how to do it, this still blows my mind.
Just now, I punched " 23/990 "into my calculator, and stared in wonder
and amazement when " 0.023232323 " came up.
1/ 816
Step-by-step explanation:
Step 1 :
Given
Total number of students in the school = 18
Number of students randomly selected = 3
Step 2 :
Number of ways in which 3 students can be selected out of 18 students is
C(18,3) = 18! /(3!(*18-3)!) = 18*17*16/3*2*1 = 816
Number of ways in which 3 students are selected and they are the youngest = 1
Hence the probability of selecting 3 youngest students from the available students is 1/ C(18,3) = 1/ 816
