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wel
2 years ago
5

Find the surface area of a rectangular prism measuring 7yd and 3yd along the base and 9yd tall

Mathematics
1 answer:
skad [1K]2 years ago
3 0

Answer:

222 yd²

Step-by-step explanation:

Bottom and top area, each = 7 * 3 = 21 yd²

Two lateral surdaces, each = 7 * 9 = 63 yd²

Two lateral surdaces, each = 3 * 9 = 27 yd²

Total area = 2 x (21 + 63 + 27) = 222 yd²

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The graph of which function will have a maximum and a y-intercept of 4? f(x) = 4x2 + 6x – 1 f(x) = –4x2 + 8x + 5 f(x) = –x2 + 2x
Svetradugi [14.3K]

Answer:

It is f(x) = -x^2 + 2x + 4.

Step-by-step explanation:

As it has a maximum the coefficents of x^2 will be negative.

f(x) = -x^2 + 2x + 4

The y-intercept occurs when x = 0 so

y-intercept = 0 + 0 + 4 = 4.

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3 years ago
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An algorithm takes 0.5 seconds to run on an input of size 100. How long will it take to run on an input of size 1000 if the algo
dexar [7]

Answer:

linear: 5s

quadratic: 50s

log-linear: 0.75 s

cubic: 500s

Step-by-step explanation:

Let t_1,t_2 be the running time associated with the input of sizes s_1,s_2

If the running time is linear

t_2 = t_1\frac{s_2}{s_1} = 0.5*\frac{1000}{100} = 0.5*10 = 5s

If the running time is quadratic

t_2 = t_1\left(\frac{s_2}{s_1}\right)^2 = 0.5*\left(\frac{1000}{100}\right)^2 = 0.5*10^2 = 50s

If the running time is log-linear

t_2 = t_1\frac{log(s_2)}{log(s_1)} = 0.5*\frac{log(1000)}{log(100)} = 0.5*1.5 = 0.75s

If the running time is cubic:

t_2 = t_1\left(\frac{s_2}{s_1}\right)^3 = 0.5*\left(\frac{1000}{100}\right)^3 = 0.5*10^3 = 500s

6 0
3 years ago
What is the approximate surface area of a cylinder with a radius of 3 inches and a height of 10 inches?
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245in^2

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5 0
3 years ago
Alaine has 1 gallon of paint. She is going to pour it into a paint tray that measures 10 inches wide, 12 inches long, and 5 cm d
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Answer:

Is 10B and you get like 1000

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