Answer:
2y-x=6
Step-by-step explanation:
Standard form is ax+by=c.
Slope form : y=mx+n where m is slope n-y intercept.
First we write in slope form
Now we can multiply both sides by 2.
2y=x+6
Subtract for each side x
2y-x=6
The total area is:
A = Ab + Al
Where,
Ab: base area
Al: lateral area
We have then:
For the base area:
Ab = (2) * (2)
Ab = 4 units ^ 2
For the lateral area:
Al = (4) * (1/2) * (2) * (root ((1) ^ 2 + (3) ^ 2))
Al = (4) * (root (1 + 9))
Al = 4raiz (10) units ^ 2
Total area:
A = 4 + 4raiz (10)
Answer:
A = 4 + 4raiz (10)
Answer + step-by-step explanation:
7/10 as a decimal would be 0.7.
7/10 or 0.7 in a word form would be seven tenths.
<em><u>Hope this helps, if my answer or explanation is wrong </u></em>
<em><u>feel free to message me in the comments :).</u></em>
- genius423
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
Answer:
2
Step-by-step explanation:
f = a
48 = 3
32 = x
48x= 98
<u>x=2</u>
<h2><u>
Mark me as brainiest if i helped you </u></h2>
