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Answer:
Divide by 2
q^2+4q=3/2
q^2+4q(4/2)^2=3/2+(4/2)^2
(q+4/2)^2=3/2+16/4
taking the square root of both side
√(q+4/2)^2=√(3/2+16/4)
Note that the square will cancel the square root then you will take LCM on the right hand side
q+4/2=√6+16/4
q+4/2=√22/4
q= -4/2+-√22/4
q=(-4+_√22/4)
Answer:
1.2218 atm
Step-by-step explanation:
From ideal gas formula,
PV=nRT
Where n= number of moles
V= volume
T= temperature=25.0°C
= (273 + 25) = 298 K
R= gas constant = 0.082 l atm /K mol.
Making P subject of formula we have
P= [nRT] /V
Then substitute the values we have
P= [0.5 x 0.082 x 298] / 10
P= 1.2218 atm
Answer:
8q + 6 = 8*2 + 6 = 16 + 6 = 22
The answer for your question is 12/15
