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Alex777 [14]
2 years ago
11

Please help I know how to do this but there’s too much

Mathematics
1 answer:
Lady_Fox [76]2 years ago
6 0

Answer: See attached images

Step-by-step explanation:

For third period:

Minimum = 67

1st Quartile: 79.5

Median/2nd Quartile: 85

3rd Quartile: 90.5

Maximum = 99

I've attached the image for this class's box plot.

For Sixth Period:

Minimum = 70

1st Quartile: 79.5

Median/2nd Quartile: 88

3rd Quartile: 90.5

Maximum = 95

I've also attached the image for this class's box plot

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RoseWind [281]
They both seem to be substitution
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Missing angles in triangle help
Dmitry [639]

Answer:

which one?

Step-by-step explanation:

6 0
3 years ago
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You are trying to cast four roles for a play. 12 actors try out, including sir Ian McKellen and Patrick Stewart. the director te
Komok [63]

Answer:

6,840 casts

Step-by-step explanation:

Assuming that every actor can play each of the 4 roles and that each role is different, the number of possible casts including at least one of sir Ian and Patrick is given by the total number of possible casts (permutation of 4 out of 12 actors), minus the number of casts without sir Ian and Patrick (permutation of 4 out of 10 actors):

n=\frac{12!}{(12-4!)} -\frac{10!}{(10-4)!}\\n=(12*11*10*9)-(10*9*8*7)\\n=6,840\ casts

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8 0
3 years ago
1. Do you the following side lengths form a right triangle?2. Which measurement is closest to the value of X in centimeters?
koban [17]

Answer:

Part 1:

Yes, the side lengths form a right triangle.

Part 2:

Option d 37.1 cm

Explanation:

We need to use the pythagorean theorem.

In part 1, if the 3 side lengths are a right triangle, then, they must verify:

7.5^2=4.5^2+6^2

By the theorem. Then:

\begin{gathered} 7.5^2=56.25 \\ 4.5^2+6^2=20.25+36=56.25 \end{gathered}

They're equal, then the lengths correspond to a right triangle.

For part 2, we need to use again the theorem. In this case:

\begin{gathered} 12^2+x^2=39^2 \\ x=\sqrt{1521-144} \\ x=\sqrt{1377} \\ x\approx37.1cm \end{gathered}

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1 year ago
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26 x 112.5 == 2,925.
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