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3 years ago

Anna and Betty share 24 sweets in the ratio 3:5. How many sweets do they get each?

Mathematics

1 answer:

Alborosie3 years ago

3 0

Answer:

Anna 9 and Betty 15

Step-by-step explanation:

sum the parts of the ratio , 3 + 5 = 8 parts

divide number of sweets by 8 to find value of one part of the ratio

24 ÷ 8 = 3 ← value of 1 part of the ratio , then

3 parts = 3 × 3 = 9

5 parts = 5 × 3 = 15

Anna gets 9 sweets and Betty gets 15

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Match the following items.

charle [14.2K]

Answer:

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3: BC = BD 3: Substitution

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Step-by-step explanation:

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3 years ago

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A 100 cm² b 9 cm² c 225 cm² d 28.26 cm²

nasty-shy [4]

Answer:

28.26 cm^2

Step-by-step explanation:

A = (pi)r^2

A = 3.14 * (3 cm)^2

A = 3.14 * 9 cm^2

A = 28.26 cm^2

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3 years ago

1. Simplify this expression: 13+ (-12) - (-5) = ? O A.-30 O B.6 O C.30 OD. -6

Virty [35]

Answer:

B.6

Step-by-step explanation:

When we add and subtract, we do it from left to right

13+ (-12) - (-5)

13+-12

13-12 = 1

1 - -5

A negative negative is a positive

1 +5

8 0

3 years ago

Read 2 more answers

A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

Thus the daily expense in dollars can be given by = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

Tour duration now = $(x+4)$ days

On extension, his daily expense is cut by $3

New daily expense in dollars = $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

$(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))$

$360-3x+\frac{1440}{x}-12$

$348-3x+\frac{1440}{x}$

We know total expense remains the same which is = $360.

So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

$-3x^2+1440=12x$

Dividing each term with -3.

$\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}$

$x^2-480=-4x$

Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16+1920}}{2}$

$x=\frac{-4\pm\sqrt{1936}}{2}$

$x=\frac{-4\pm44}{2}$

So, we have

$x=\frac{-4+44}{2}$ and $x=\frac{-4-44}{2}$

$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

∴ $x=20$ and $x=-24$

Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

6 0

3 years ago

2. In the triangle below, NE and KL are perpendicular bisectors. Knowing that the sum of interior angles in

Stells [14]

Answer:

a = 60°

Step-by-step explanation:

From the picture attached,

In the given triangle,

NE and ML are the perpendicular bisectors of two sides of the triangle.

Therefore, m∠MEK = m∠MLK = 90°

Since, sum of interior angles of polygon KLME = 360°

m∠MEK + m∠MLK + m∠EML + m∠EKL = 360°

90° + 90° + 120° + a = 360°

a = 360° - 300°

a = 60°

5 0

3 years ago