Will mark brainliest pls help

What is the approximate age of a woman whose normal systolic pressure measures 125 mm Hg?

sashaice [31]

The approximate age of a woman whose normal systolic pressure measures 125 mm Hg is 31

The function is given as:

$P(A) = 0.006A^2 - 0.02A + 120$

When the normal systolic pressure is 125, it means that:

$P(A) = 125$

So, we have:

$125 = 0.006A^2 - 0.02A + 120$

Subtract 125 from both sides of the equation

$0= 0.006A^2 - 0.02A + 120 -125$

$0= 0.006A^2 - 0.02A - 5$

Rewrite the equation as:

$0.006A^2 - 0.02A - 5 = 0$

Using a graphing calculator, we have:

$A = \{30.58, -27.25\}$

But age cannot be negative.

So, we have:

$A = 30.58$

Approximate

$A =31$

Hence, the age of the woman is 31

Read more about quadratic functions at:

brainly.com/question/11441586

8 0

2 years ago

Read 2 more answers

In the basketball game a player scored 4 three-pointers. How many points did he achieve with the 8 three-pointers?

Bogdan [553]

He scored 24 points which means that after scoring the 4 three pointers, he would have to score another 4 three pointers (12 points)

6 0

2 years ago

Find all of the zeros of each function <br>x^3+9x^2+6x-16

dedylja [7]

Answer:

x = -8, -2, and 1

Step-by-step explanation:

The zeros of a function are another name for its x-intercepts. To find them, graph the function and examine its behavior near the x-axis. In the attached picture you can see that this function has the zeros, x = -8, -2, and 1.

6 0

3 years ago

PLZ HELP ASAP MARKIN BRAINIEST !!!

zzz [600]

Put a dot on -7 and -1 so the slope is 3 over 2x for the first inequality and the y is -1 do rise over run for each the slope for second is 1 over 1 put a dot for both on y axis (:

3 0

3 years ago

A supplier of heavy construction equipment has found that new customers are normally obtained through customer requests for a sa

ziro4ka [17]

Answer:

The probability that it will take fewer than six customer contacts to clear the inventory is 0.8%.

Step-by-step explanation:

We have a probability of making an individual sale of p=0.15.

We have 4 units, so the probability of clearing the inventory with n clients can be calculated as:

$P=\dbinom{n}{4}p^4q^{n-4}=\dbinom{n}{4}0.15^4\cdot 0.85^{n-4}$

As we see in the equation, n has to be equal or big than 4.

In this problem we have to calculate the probability that less than 6 clients are needed to sell the 4 units.

This probability can be calculated adding the probability from n=4 to n=6:

$P=\sum_{n=4}^6P(n)=\sum_{n=4}^6 \dbinom{n}{4}0.15^4^\cdot 0.85^{n-4}\\\\\\P=0.15^4(\dfrac{4!}{4!0!}\cdot 0.85^{4-4}+\dfrac{5!}{4!1!}\cdot0.85^{5-4}+\dfrac{6!}{4!2!}0.85^{6-4})\\\\\\P=0.15^4(1\cdot0.85^0+5\cdot0.85^1+15\cdot0.85^2)\\\\\\P=0.00051(1+4.25+10.84)\\\\\\P=0.00051\cdot16.09\\\\\\P=0.008$

5 0

3 years ago