If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) in terms of n?
1 answer:
Answer:
t(d(n)) = 12n + 7
Step-by-step explanation:
- t(d) = 3d + 1
- d(n) = 4n + 2
<u>t(d(n)) = t(4n + 2) </u>
Substitute the function d(n) into the function t(d) for the variable d.
t(4n + 2) = 3(4n + 2) + 1
t(d(n)) = 12n + 7
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hope this helps :3
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