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2 years ago

If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) in terms of n?

Mathematics

1 answer:

Basile [38]2 years ago

5 0

Answer:

t(d(n)) = 12n + 7

Step-by-step explanation:

t(d) = 3d + 1
d(n) = 4n + 2

Substitute the function d(n) into the function t(d) for the variable d.

t(4n + 2) = 3(4n + 2) + 1

12n + 6 + 1
12n + 7

t(d(n)) = 12n + 7

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