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Luden [163]
2 years ago
8

If t(d) = 3d + 1 and d(n) = 4n + 2, what is t(d(n)) in terms of n?

Mathematics
1 answer:
Basile [38]2 years ago
5 0

Answer:

t(d(n)) = 12n + 7

Step-by-step explanation:

  • t(d) = 3d + 1
  • d(n) = 4n + 2

<u>t(d(n)) = t(4n + 2) </u>

Substitute the function d(n) into the function t(d) for the variable d.

t(4n + 2) = 3(4n + 2) + 1  

  • 12n + 6 + 1
  • 12n + 7

t(d(n)) = 12n + 7

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hope this helps :3

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