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RideAnS [48]
3 years ago
6

Solve. e^(4x) + 5e^(2x) - 24 = 0.

Mathematics
1 answer:
harina [27]3 years ago
8 0
E^2x=yso e^(4x) + 5e^(2x) - 24 = 0=y^2+5y-24=(y+8)(y-3)y=3ln3=2xx=ln(3)/2=0.55
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For what values of q are the two vectors A = i + j + kq each other and B-iq-23 + 2kg perpendicular to
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Answer:

The value of q are 0.781,-1.281.

Step-by-step explanation:

Given : Two vectors A=i+j+kq and B=iq-2j+2kq are perpendicular to each other.

To find : The value of q ?

Solution :

When two vectors are perpendicular to each other then their dot product is zero.

i.e. \vec{A}\cdot \vec{B}=0

Two vectors A=i+j+kq and B=iq-2j+2kq

(i+j+kq)\cdot (iq-2j+2kq)=0

(1)(q)+(1)(-2)+(q)(2q)=0

q-2+2q^2=0

2q^2+q-2=0

2q^2+q-2=0

Using quadratic formula,

q=\frac{-1\pm\sqrt{1^2-4(2)(-2)}}{2(2)}

q=\frac{-1\pm\sqrt{17}}{4}

q=\frac{-1+\sqrt{17}}{4},\frac{-1-\sqrt{17}}{4}

q=0.781,-1.281

Therefore, The value of q are 0.781,-1.281.

6 0
3 years ago
What is (3.9 x 10 to the power of 33) times (3.25 x 10 to the power of 3)
Anna35 [415]

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Step-by-step explanation:

3.9x10^33 x 3.25x10^3

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12.675x10^36

1.2675x10^1x10^36

1.2675x10^(1+36)

1.2675x10^37

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3 years ago
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Step-by-step explanation:

C is the solution

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