If two planes cross one another, the their intersection is 2 lines?

Mathematics

1 answer:

motikmotik3 years ago

6 0

Umm lol if its (2) planes CROSSING ANOTHER then that means there intersection is (2) lines :) :(

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Martha Washington walks 30 minutes each day. If she walks for 140 days, how many hours will she walk?

telo118 [61]

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2 years ago

The perimeter of the square can be represented by the expression 36x+44 robin wants to write an equivalent expression for the pe

sukhopar [10]

Answer:

4 (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is (9 x + 11).

Step-by-step explanation:

Here, given The perimeter of the square = (36 x+44)

Now,as we know :

PERIMETER OF SQUARE = 4 x ( SIDES)

Simplifying the perimeter expression.

Take 4 common out of the expression (36 x+44), we get:

(36 x+44) = 4 (9 x + 11)

⇒ Perimeter of the square = 4 x (9 x + 11)

⇒4 x ( SIDES) = 4 x (9 x + 11)

⇒ Each Side = (9 x + 11)

Hence, 4 x (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is (9 x + 11).

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3 years ago

Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD

Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = $\sqrt{75+25}$ = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that $\frac{1}{2} * BF = \frac{1}{2} * 5 * \sqrt{75}$ and BF= $0.5\sqrt{75}$ . Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is $A= BF * \frac{AB+CD}{2} = 0.5 \sqrt{75} * \frac{5+10}{2} = 18.75 \sqrt{3} cm^{2}$