Answer:
a_n = 2^(n - 1) 3^(3 - n)
Step-by-step explanation:
9,6,4,8/3,…
a1 = 3^2
a2 = 3 * 2
a3 = 2^2
As we can see, the 3 ^x is decreasing and the 2^ y is increasing
We need to play with the exponent in terms of n
Lets look at the exponent for the base of 2
a1 = 3^2 2^0
a2 = 3^1 2^1
a3 = 3^ 0 2^2
an = 3^ 2^(n-1)
I picked n-1 because that is where it starts 0
n = 1 (1-1) =0
n=2 (2-1) =1
n=3 (3-1) =2
Now we need to figure out the exponent for the 3 base
I will pick (3-n)
n =1 (3-1) =2
n =2 (3-2) =1
n=3 (3-3) =0
1/7 + x = 2/3x
1/7 = 2/3x-x
1/7 = 2/3x - 1x
1/7 = -1/3x
-3/7 = x
The first thing you should do when dealing with implicit derivatives is to respect the rules of derivation of both the logarithm and the exponential
Then, you must regroup the terms correctly until you get dy / dx
The answer for this case is D
I attach the solution
Fruits :
Y=10(h)
Flowers;
Y=8(h)
Given: h=6
Fruits:
10(6) = $60
Flowers:
8(6)= $48
Back to the question, how much more from picking fruits?
$60 - $48 = $12 more picking fruits.
Hope this helps!