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Ronch [10]
3 years ago
12

Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him ₹ 50 per metre and trousers material

that costs him ₹ 90 per metre. For every 3 metres of the shirt material, he buys 2 metres of the trouser material. He sells the materials at 12% and 10% profit respectively. His total sale is ₹ 36,600. How much trouser material did he buy?
PLease i want it with step by step explanation
Mathematics
1 answer:
True [87]3 years ago
5 0

Answer:

Step-by-step explanation:

Let x represent the number of meters of shirt material that he bought.

Let y represent the number of meters of trouser material that he bought.

For every 3 metres of the shirt material, he buys 2 metres of the trouser material. It means that

2x = 3y

x = 3y/2

shirt material cost him ₹ 50 per metre and trousers material cost him ₹ 90 per metre. It means that the total cost is

50x + 90y

Selling price for the shirt material is

50x + (12/100 × 50x) = 56x

Selling price for the trouser material is

90y + (10/100 × 90y) = 99y

If his total sale is ₹ 36,600, it means that

56x + 99y = 36600- - - - - - - - 1

Substituting x = 3y/2 into equation 1, it becomes

56(3y/2) + 99y = 36600

Multiplying both sides by 2, it becomes

168y + 198y = 73200

366y = 73200

y = 73200/366

y = 200

x = 3y/2 = 3 × 200/2

x = 300

He bought 200 meters of trouser material

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7 0
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Answer:
Step-by-step explanation:
We would apply the simple interest formula which is expressed as
I = PRT/100
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