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exis [7]
2 years ago
9

For a school fundraiser, Elena will make pirate masks. She will order masks and print graphics on them. Elena must spend $349 on

the printer before she can print any masks and then $4.80 on each mask. If she has $997 how many masks can she print? Answer as a number!
Mathematics
2 answers:
SpyIntel [72]2 years ago
6 0

Answer:

135 masks

Step-by-step explanation:

i hope my math is right lol

Alex Ar [27]2 years ago
5 0

Answer:

135 masks

Step-by-step explanation:

First, we take $997 and subtract that by $349

$997 - $349 = $648

To find how many masks Elena can print, we divide $648 dollars by $4.80. Since one mask is equivalent to $4.80

$648 ÷ $4.80 = 135

135 masks

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Law Incorporation [45]

Eleven feet and two.five inches

8 0
3 years ago
Read 2 more answers
12x - 24 + 3x = 1/3x + 4 + 10x plz no link or spam (i will report you)
Sphinxa [80]

Answer:

x=6

15x - 24 = 1/3x + 4 + 10x

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45x - 72 = x + 12 + 30x

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45x - 72 = 31x + 12

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45x - 31x = 12 + 72

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14x = 84

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x = 6

3 0
2 years ago
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
8)
mixer [17]
Did you already find the answer?
6 0
2 years ago
Can someone help me solve this expression?
user100 [1]

Answer:

2x-12

Step-by-step explanation:

First you distribute the -2 to the x and +3

this will make you expression be:

4x-6-2x-6

you then do -6+-6

this will make your expression be:

4x-12-2x

After you get this you have to combine like terms. the like terms in the expression are the two with x being you variable. 4x and -2x.

Once you have combined like terms your solution should be:

2x-12

8 0
3 years ago
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