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3 years ago

Simplify (2x + y)(x - 2y) - (x + 2y)(2x - y) as much as possible.

Mathematics

1 answer:

snow_tiger [21]3 years ago

4 0

Answer:

-6xy

Step-by-step explanation:

(2x-y)x(x-2y)-(x+2y)X(2x-y)

remove the parentheses

2x^2-4xy+xy-2y^2-(2x^2-xy+4xy-2y^2)

collect terms

2x^2-4xy+xy-2y^2-(2x^2+3xy-2y^2)

remove the parentheses

2x^2-4xy+xy-2y^2-2x^2-3xy+2y^2

remove the opposites, collect the terms to get -6xy

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Factor the algebraic expression 21a + 9

vladimir2022 [97]

Answer:

21a + 9

Simplifying

21a + 9

Reorder the terms:

9 + 21a

Factor out the Greatest Common Factor (GCF), '3'.

3(3 + 7a)

Final result:

3(3 + 7a)

HOPE THIS HELP

6 0

3 years ago

Read 2 more answers

Answer ASAP THANKKK YOUUUUU

alexandr402 [8]

Answer:

D. 40

Step-by-step explanation:

Interquartile range is the difference between the upper quartile value (Q3) and the lower quartile value (Q1).

In a box plot, Q1 is located at the beginning of the edge of the rectangular box from our left, while the Q3 is located at the end of the edge of the rectangular box to our right.

Interquartile range for City A = 70 - 40 = 30

Interquartile range for City B = 80 - 40

Therefore, city B has greater variability. The interquartile range is 40.

7 0

3 years ago

How do i do fifth grade divison

ser-zykov [4K]

Ummm like long division

6 0

3 years ago

Last week, Sarah had exams in Math, Spanish, and English. On the Math exam, the mean was µ = 30 with s = 5, and Sarah had a scor

serious [3.7K]

Answer:

Sara expect the better grade for Math class.

Step-by-step explanation:

Consider the provided information.

On the Math exam, the mean was µ = 30 with s = 5, and Sarah had a score of X = 45.

Z score for Math: $Z=\frac{x-\mu}{s}$

$Z=\frac{45-30}{5}$

$Z=\frac{15}{5}$

$Z=3$

On the Spanish exam, the mean was µ = 60 with s = 8 and Sarah had a score of X = 68.

Z score for Spanish: $Z=\frac{x-\mu}{s}$

$Z=\frac{68-60}{8}$

$Z=\frac{8}{8}$

$Z=1$

On the English exam, the mean was µ = 70 with s = 8 and Sarah had a score of X = 70.

Z score for English: $Z=\frac{x-\mu}{s}$

$Z=\frac{70-70}{8}$

$Z=0$

We can observe that Z score of Math is greater than Spanish and English.

Which means that Sarah did the best in her Math exam.

Hence, Sara expect the better grade for Math class.

8 0

3 years ago

write the standard form of the equation of the circle for which the endpoints of a diameter are (0,0) and (4,-6)

Elenna [48]

Given:

The endpoints of a diameter are (0,0) and (4,-6).

To find:

The equation of the circle.

Solution:

The endpoints of a diameter are (0,0) and (4,-6). So, the length of the diameter is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-6-0)^2+(4-0)^2}$

$d=\sqrt{36+16}$

$d=\sqrt{52}$

$d=2\sqrt{13}$

Now, radius is half of the diameter.

$r=\dfrac{2\sqrt{13}}{2}$

$r=\sqrt{13}$

Center of the circle is the midpoint of the endpoints of a diameter.

$Center=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Center=\left(\dfrac{0+4}{2},\dfrac{0+(-6)}{2}\right)$

$Center=\left(\dfrac{4}{2},\dfrac{-6}{2}\right)$

$Center=\left(2,-3\right)$

Standard form of a circle is

$(x-h)^2+(y-k)^2=r^2$

where, (h,k) is center and r is radius.

The center of the circle is (2,-3) and radius is $\sqrt{13}$ . So,

$(x-2)^2+(y-(-3))^2=(\sqrt{13})^2$

$(x-2)^2+(y+3)^2=13$

Therefore, the standard form of the circle is $(x-2)^2+(y+3)^2=13$ .

5 0

3 years ago