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e-lub [12.9K]
2 years ago
5

(x+2) (x+1)=0

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
4 0

Answer:

x=\begin{bmatrix}-2\\-1\\\end{bmatrix}

Step-by-step explanation:

(x+2) (x+1)=0

Isolate the X

=> \left(x+2\right)\left(x+1\right)=0

Divide both sides by the coefficient:

=>x=\begin{bmatrix}-2\\-1\\\end{bmatrix}

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I really need help >_< please and thank you
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First, find the slope. To calculate slope, count the rise (how many units up or down) the line goes from any point to the next immediate point, then the run (how many units left or right.) This should leave you with a fraction, rise/run. For example, on number 3, from labeled points (-5, -4) to (5,2) (double check cause it’s hard to see on my phone, but i think those are the points on 1??) it rises 6 units (-4 to 2) and runs 10 units (-5 to 5). This gives you your rise/run fraction, which is 6/10, simplified to 3/5.

So the slope fills out the m part of the equation. For 3, we found that slope is 3/5, and that fits into the m variable of the slope equation.

This makes it y=3/5x+b.

The last (and considerably less confusing) step is to find b. b is the y-intercept, which is just the point in the graph where the line crosses the y-axis and x=0. On 3, this would be (0,-1) or just -1.

So fill -1 into the b slot of the equation, and you get y=3/5x-1. And thats it!!

Let me know if you still need help on any of the other problems, but I hoped this helped to clear it up!! :)


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