Answer:
<em>D.) 0</em>
Step-by-step explanation:
Its not A. cause 2y−2=0 is y = 1
Its not B. cause 2y−1=0 is y = 1/2
Its not C. cause 2y−3=0 is y = 3/2
Soo... The only option left is D.
It IS D. cause 2y − 0 = 0 is y=0
<em>So you are Correct!!!</em>
<em>hope I helped... <3</em>
<em>Good luck dear :)</em>
keep in mind, that "t" is the time when the train at A station, left towards B station
they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference
Answer:
The correct option is C
Step-by-step explanation:
A: We know that the lower quartile is 144, and the upper quartile is 129.5 is you add them all up it is going to equal 273.3. So we know that A can now be crossed out.
B: We know that the lower quartile is 146, and that means the upper quartile is 136.5. So adding all of these numbers up we ill get 282.5 So now <u>B can be crossed out</u>
C: The lower quartile is 114 and the upper quartile is 129.5 and when we add those two numbers up we are going to get 243.5. So we are going to keep this number
D: For the last one we know the lower quartile is 214 and upper is 129.5, and when we add this we get 343.5. So we can cross this out and<u> the only one we have left is going to be C</u>
<u>Hope this help's</u>
Answer:
Salena's got to the library first
Step-by-step explanation:
12½ miles = 25/2 miles
2½ miles = 5/2 miles
5¾ miles = 23/4 miles
114 miles = 114 miles
Salena's time of arrival =
if 5/2 miles : 5 minutes
then 25/2 miles : ?
25/2 ÷ 5/2. × 5
25/2 × 2/5 × 5
25 minutes
Justin 's time of arrival=
if 23/4 miles : 12 minutes
25/2 miles : ?
25/2 ÷ 23/4 ×12
25/2 × 4/23 ×12
26 minutes approximately
Brandon 's time of arrival=
if 114 miles : 258 minutes
25/2 miles : ?
25/2 ÷114 ×258
25/2 × 1/114×258
25 × 1/57 × 258
113 minutes approximately
