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leva [86]
2 years ago
8

Find the slope between (2, 5) and (7,3).

Mathematics
1 answer:
beks73 [17]2 years ago
7 0

Answer:

-2/5

Step-by-step explanation:

y2-y1

--------      is -2/5 .  after . u plug the 2 pairs

x2-x1

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Q2-b2Evaluate if a=4 and b =-2​
lesya692 [45]

Answer:

12

Step-by-step explanation:

Plug the given values into the equation to solve.

a² - b²

(4)² - (-2)²

16 - 4

12

7 0
3 years ago
Write the number 2 and a half million in figures
inysia [295]
The answer is 2 500 000
6 0
3 years ago
Is it a convenience sample or voluntary response sample for both
Katyanochek1 [597]

Answer:

both of the questions are examples of convenience samples

Step-by-step explanation:

A voluntary response would be where the people get to choose to respond to the survey. In both of these cases, teachers are specifically asking for their students opinions.

7 0
3 years ago
Please help Which of the following inequalities is graphed on the coordinate plane?
Gekata [30.6K]

Answer:

The inequality which represents the graph is y ≤ -2x + 1 ⇒ A

Step-by-step explanation:

To solve the question you must know some facts about inequalities

  • If the sign of inequality is ≥ or ≤, then it represents graphically by a solid line
  • If the sign of inequality is > or <, then it represents graphically by a dashed line
  • If the sign of inequality is > or ≥, then the area of the solutions should be over the line
  • If the sign of inequality is < or ≤, then the area of the solutions should be below the line

Let us study the graph and find the correct answer

∵ The line represented the inequality is solid

∴ The sign of inequality is ≥ or ≤

→ That means the answer is A or B

∵ The shaded area is the area of the solutions of the inequality

∵ The shaded area is below the line

∴ The sign of inequality must be ≤

→ That means the correct answer is A

∴ The inequality which represents the graph is y ≤ -2x + 1

3 0
3 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0
3 years ago
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