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mart [117]
2 years ago
15

Y

Mathematics
1 answer:
Luba_88 [7]2 years ago
3 0

Answer:

a

Step-by-step explanation:

y\leq\frac{1}{2}x+2 \\\\1\leq \frac{1}{2}(0)+2\\\\1\leq 0+2\\\\1\leq 2

This statement is true

Hope this helps!

You might be interested in
A chess team has 26 members. However, only 16 members attended the last meeting: half of the girls attended but all of the boys
madam [21]
26-16=10. So I believe it would be 10 girls and 6 boys.
6 0
2 years ago
Reliance on solid biomass fuel for cooking and heating exposes many children from developing countries to high levels of indoor
kherson [118]

Answer:

A) 95% confidence interval for the population mean PEF for children in biomass households = (3.314, 3.486)

95% confidence interval for the population mean PEF for children in LPG households

= (4.195, 4.365)

Simultaneous confidence interval for both = (3.314, 4.365)

B) The result of the hypothesis test is significant, hence, the true average PEF is lower for children in biomass households than it is for children in LPG households.

C) 95% confidence interval for the population mean FEY for children in biomass households = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.365)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Step-by-step explanation:

A) Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the z-distribution. This is because although, there is no information provided for the population standard deviation, the sample sizes are large enough for the sample properties to approximate the population properties.

Finding the critical value from the z-tables,

z-critical value for 95% confidence level = 1.960 (from the z-tables)

For the children in the biomass households

Sample mean = 3.40

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.20

N = sample size = 756

σₓ = (1.20/√756) = 0.04364

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 3.40 ± (1.960 × 0.04364)

CI = 3.40 ± 0.08554

95% CI = (3.31446, 3.48554)

95% Confidence interval = (3.314, 3.486)

For the children in the LPG households

Sample mean = 4.28

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation of the sample = 1.19

N = sample size = 752

σₓ = (1.19/√752) = 0.043395

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 4.28 ± (1.960 × 0.043395)

CI = 4.28 ± 0.085054

95% CI = (4.1949, 4.3651)

95% Confidence interval = (4.195, 4.365)

Simultaneous confidence interval for both = (3.214, 4.375)

B) The null hypothesis usually goes against the claim we are trying to test and would be that the true average PEF for children in biomass households is not lower than that of children in LPG households.

The alternative hypothesis confirms the claim we are testing and is that the true average PEF is lower for children in biomass households than it is for children in LPG households.

Mathematically, if the true average PEF for children in biomass households is μ₁, the true average PEF for children in LPG households is μ₂ and the difference is μ = μ₁ - μ₂

The null hypothesis is

H₀: μ ≥ 0 or μ₁ ≥ μ₂

The alternative hypothesis is

Hₐ: μ < 0 or μ₁ < μ₂

Test statistic for 2 sample mean data is given as

Test statistic = (μ₂ - μ₁)/σ

σ = √[(s₂²/n₂) + (s₁²/n₁)]

μ₁ = 3.40

n₁ = 756

s₁ = 1.20

μ₂ = 4.28

n₂ = 752

s₂ = 1.19

σ = √[(1.20²/756) + (1.19²/752)] = 0.061546

z = (3.40 - 4.28) ÷ 0.061546 = -14.30

checking the tables for the p-value of this z-statistic

Significance level = 0.01

The hypothesis test uses a one-tailed condition because we're testing in only one direction.

p-value (for z = -14.30, at 0.01 significance level, with a one tailed condition) = 0.000000001

The interpretation of p-values is that

When the p-value > significance level, we fail to reject the null hypothesis and when the p-value < significance level, we reject the null hypothesis and accept the alternative hypothesis.

Significance level = 0.01

p-value = 0.000000001

0.000000001 < 0.01

Hence,

p-value < significance level

This means that we reject the null hypothesis, accept the alternative hypothesis & say that true average PEF is lower for children in biomass households than it is for children in LPG households.

C) For FEY for biomass households,

Sample mean = 2.3 L/s

Standard error of the mean = σₓ = (σ/√N)

σ = standard deviation = 0.5

N = sample size = 756

σₓ = (0.5/√756) = 0.018185

95% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 2.30 ± (1.960 × 0.018185)

CI = 2.30 ± 0.03564

95% CI = (2.264, 2.336)

Simultaneous confidence interval for both = (2.264, 4.365)

This simultaneous interval cannot be the same as that calculated in (a) above because the sample mean obtained for children in biomass households here (using FEY) is much lower than that obtained using PEF in (a).

Hope this Helps!!!

3 0
2 years ago
Help me now !!!!!<br> help i need help
iren2701 [21]

cylinder:

V = πr²h

V = 3.14(2)² * 3

V = 3.14(4) * 3

V = 3.14(12)

V = 37.7m³

rectangular prism:

V = lwh

V = (2.4)(9)(5)

V = 108m³

the entirety of the sculpture:

V = volume of cylinder + volume of rectangular prism

V = 37.7 + 108

<u>V = 145.7m³</u>

4 0
1 year ago
30 points + brainliest if correct.
Dovator [93]

I think d but im not sure


3 0
3 years ago
Read 2 more answers
A lab orders a shipment of 100 rats a week for experiments that the lab conducts. Prices for each weekly shipment of rats follow
Korolek [52]

Answer:

Therefore, the budget is 656.76$.

Step-by-step explanation:

We know that a lab orders a shipment of 100 rats a week for experiments that the lab conducts. Suppose the mean cost of the rats turned out to be $ 12.63 per week. We calculate budget of a lab for the next year's.

We know that 1 year have 52 weeks. We get

52 · 12.63 = 656.76

Therefore, the budget is 656.76$.

4 0
3 years ago
Read 2 more answers
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