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ludmilkaskok [199]
1 year ago
6

When you flip a biased coin the probability of getting a tail is 0.75.

Mathematics
1 answer:
Blababa [14]1 year ago
5 0

Answer:

180

Step-by-step explanation:

It's 180 because 75% of 240 is 180.

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(3x + 1/2 ) + ( 7x - 4 1/2 ) simply the expression
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(3x + 1/2 ) + ( 7x - 4 1/2 )

3x+7x + 1/2 - 4 1/2

10x -4

5 0
3 years ago
What is the ratio of 5 whales and 5 fish?
abruzzese [7]
1:1, because there’s a same number of both !
8 0
1 year ago
Please help me and answer correctly!
LenKa [72]
A^-b = 1/a^b
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3 0
3 years ago
Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,
Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁,  of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}

Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times  (720-576)\times  (720 - 672)}

Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times  144 \times  48} = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}

The semi-perimeter, s₂,  of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times  (690 -228)\times  (690 - 480)}

Area\, of \, \Delta ACD = \sqrt{690 \times 18\times  462\times  210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0
3 years ago
Find AB. Round the answer to the nearest tenth if needed.
Yuliya22 [10]

9514 1404 393

Answer:

  8

Step-by-step explanation:

The product of segment lengths to the near and far circle intersection points is the same for both "secants". AD is a tangent, so the two intersection points are the same point. This gives ...

  AD² = AB·AC

  144 = AB(AB +10)

We can add 25 to complete the square.

  169 = (AB +5)² . . . write as a square

  13 = AB +5 . . . . . . positive square root

  8 = AB . . . . . . . . . .subtract 5

7 0
3 years ago
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