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2 years ago

The screen shots are attatches please help i will give brainliest. inches to miles

Mathematics

2 answers:

Darina [25.2K]2 years ago

7 0

Answer:

2,500 miles per inch

Step-by-step explanation:

i devided it

tell me if i understud the question wrong

Readme [11.4K]2 years ago

5 0

2,500 miles per square inch

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Take pi to be 3.142 and write down all tge digitd given by your calculator. 21

cricket20 [7]

Answer:

3.3.14259265359 re-uccering

Step-by-step explanation:

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3 years ago

SOMEONE HELP ME PLS<br><br>I ATTACHED A PIC

crimeas [40]

Answer:

$A=54.95\ ft^2$

Step-by-step explanation:

The angle of shaded sector = 360-332 = 28°

The radius of sector, r = 15 ft

We need to find the area of the shaded sector. The formula for the area of the sector is given by :

$A=\dfrac{\theta}{360}\times \pi r^2\\\\=\dfrac{28}{360}\times 3.14\times (15)^2\\\\A=54.95\ ft^2$

So, the area of the shaded sector is equal to $54.95\ ft^2$ .

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3 years ago

kennedy has 12 apples. together, she and Ariana have 42 apples. which diagram best represents the situation where A is the amoun

Katarina [22]

There is no diagram to chose from

3 0

3 years ago

is it possible to draw a tringle with 90 Angle and one leg that is 8 centimeters long and one leg that is 6 centimeters long? is

Delvig [45]

Yes it is The hypotenuse is 10 cms long.
Because its a right angled triangle ( 90 angle) the hypotenuse will be 10 cms long - it will obey the Pythagoras theorem:-

10^2 = 8^2 + 6^2

There is only one right angled triangle with these measurements but there are many of them which have sides in same ratio

for example

3, 4 and 5

9,12 and 15

12, 16 and 20 and so on..

5 0

4 years ago

Iq scores are normally distributed with a mean of 100 and a standard deviation of 15.

bearhunter [10]

Mean is $\mu=100$ and a standard deviation is $\sigma =15$ , then the variable $X\sim N(100,15^2)$ .

Use substitution

$Z=\dfrac{X-\mu}{\sigma},\\ \\ Z=\dfrac{X-100}{15}$ .

This substitution gives you that $Z\sim N(0,1)$ .

a. For X=130, $Z=\dfrac{130-100}{15}=2$ and $Pr(X>130)=Pr(Z>2) =0.9772$ (the decimal value is taken from the Standard Normal Distribution Table).

b. For X=90, $Z=\dfrac{90-100}{15}=-\dfrac{2}{3}$ and for X=110, $Z=\dfrac{110-100}{15}=\dfrac{2}{3}$ . Then $Pr(90$ (the decimal value is taken from the Standard Normal Distribution Table).

6 0

3 years ago