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Anni [7]
3 years ago
12

If line AB is parallel to line RS, find the value of x.

Mathematics
1 answer:
kozerog [31]3 years ago
6 0

Answer: 125 degrees

Step-by-step explanation: <MTB and angle x are corresponding therefore congruent (Equal Measure) so the answer would be 125 degrees.

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Which is a characteristic of the line that passes through the points (6, 10) and (12, 7)?
mihalych1998 [28]

Answer:

Step-by-step explanation:

The general formula of the linear equation is:

y = mx + c 

where m is the slope and c is the y-intercept

1- getting the slope:

We are given the two points:

(6,10) representing (x1 , y1)

(12,7) representing (x2 , y2)

The slope of the line will be calculated as follows:

m = (y2-y1) / (x2-x1) = (7-10) / (12-6) = -3/6 = -0.5

The equation of the line now becomes:

y = -0.5x + c

2- getting the value of the y-intercept:

To get the value of the y-intercept (c), we will use any of the given points, substitute in the equation of the line and solve for c. I will use the point (6,10) as follows:

y = -0.5x + c

10 = -0.5(6) + c

10 = -3 + c

c = 13

Based on the above, the equation of the line would be:

y = -0.5x + 13

Hope this helps :)

7 0
3 years ago
Read 2 more answers
In a right triangle, theta is an acute angle and sin theta = 4/9. What is the
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3 years ago
Find the value of k if the distance between (2,k) and (6,7) is 4√2 unit​
andreyandreev [35.5K]

Answer:

k = 3

Step-by-step explanation:

We have the distance formula: d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}. We can plug in 4\sqrt{2} = d, x2 = 6, x1=2, y2 = 7, y1 = k.

Then, we can solve the question using some algebra to find that k = 3.

Edit: Here is a step by step:

4\sqrt{2} = \sqrt{(6-2)^2 + (7-k)^2}\\

(4\sqrt{2})^2 = (6-2)^2 + (7-k)^2

32 = (4)^2 + (7-k)^2

32 = 16 + (7-k)^2

32 - 16 =  (7-k)^2

16 =  (7-k)^2

\sqrt{16} =  (7-k)

4 = 7-k

k = 3

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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(a) Find the perimeter of the shape below. (Take π =<br>22/7)<br>3cm<br>3cm<br>12cm<br>20cm​
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it’s correct
3 0
3 years ago
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