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3 years ago

This figure has two intersecting lines and a ray. What is the value of x?

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

8 0

Answer:

The value of x is D. 37°

Step-by-step explanation:

No need for math on this one, the angle next to x is 71° and is significantly bigger, so the only answer could be 37°.

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3/8 rounded to the nearest thousand

tresset_1 [31]

Answer:

0.38

Step-by-step explanation:

First, we convert the fraction to a decimal number by dividing the numerator by the denominator:

3 / 8 = 0.375

There are two parts to the decimal number above:

Integer Part: 0

Fractional Part: 375

Now, we will make the Fractional Part just two digits (nearest hundredth) by using our rounding rules.*

In this case, Rule II applies, so 3/8 (or 0.375) rounded to the nearest hundredth in decimal format is:

0.38

3 0

3 years ago

Read 2 more answers

I need answers to this question, 3x-2y=8

gogolik [260]

Answer:

I guess you want the y intercept form is so the answer is:

y = $\frac{3}{2}$ x - 4

Step-by-step explanation:

3x - 2y = 8

subtract 3x from both sides

-2y = -3x + 8

divide -2 from both sides

y = $\frac{3}{2}$ x - 4

and done

8 0

1 year ago

Can someone please help me find the area of this polygon, thank you!

Amanda [17]

Answer:

Step-by-step explanation:

<h3>METHOD 1:</h3>

<em>Look at the picture</em>

We can divide a given polygon into three rectangles:

$21ft\ \times\ 10ft,\ 4ft\ \times\ 6ft,\ 6ft\ \times\ 6ft$

The formula of an area of a rectangle <em>l × w </em>:

$A=l\cdot w$

Calculate the area of each of the rectangles:

$A_1=(21)(10)=210\ ft^2\\\\A_2=(4)(6)=24\ ft^2\\\\A_3=(6)(6)=36\ ft^2$

The area of the given polygon:

$A=A_1+A_2+A_3\\\\A=210+24+36=270\ ft^2$

<h3 /><h3>METHOD 2:</h3>

<em>Look at the second picture</em>.

We subtract the field of the smaller rectangle (<em>11ft × 6ft</em>) from the field of the large rectangle (<em>21ft × 16ft</em>):

$A_S=(11)(6)=66\ ft^2\\\\A_L=(21)(16)=336\ ft^2\\\\A=A_L-A_S\to A=336-66=270\ ft^2$

7 0

3 years ago

Points A and B have coordinates (3,1,2) and (1,-5,4) respectively. Point C lies on line AB such that AC:BC=3:2. Find position ve

Sever21 [200]

Answer:

The position vector of point C is <-3 , -17 , 8> or -3i - 17j + 8k

Step-by-step explanation:

* Lets revise how to solve the problem

- If the endpoints of a segment are (x1 , y1 , z1) and (x2 , y2 , z2), and

point (x , y , z) divides the segment externally at ratio m1 :m2, then

$x=\frac{m_{1}x_{2}-m_{2}x_{1}}{m_{1} -m_{2}},y=\frac{m_{1}y_{2}-m_{2}y_{1}}{m_{1}-m_{2}},z=\frac{m_{1}z_{2}-m_{2}z_{1}}{m_{1}-m_{2}}$

* Lets solve the problem

∵ AB is a segment where A = (3 , 1 , 2) and B = (1 , - 5 , 4)

∵ Point C lies on line AB such that AC : BC=3 : 2

∵ From the ratio AC = 3/2 AB

∴ C divides AB externally

- Lets use the rule above to find the coordinates of C

- Let Point A is (x1 , y1 , z1) , point B is (x2 , y2 , z2) and point C is (x , y , z)

and AC : AB is m1 : m2

∴ x1 = 3 , x2 = 1

∴ y1 = 1 , y2 = -5

∴ z1 = 2 , z2 = 4

∴ m1 = 3 , m2 = 2

- By using the rule above

∴ $x=\frac{3(1)-2(3)}{3-2}=\frac{3-6}{1}=\frac{-3}{1}=-3$

∴ $y=\frac{3(-5)-2(1)}{3-2}=\frac{x=-15-2}{1}=\frac{-17}{1}=-17$

∴ $z=\frac{3(4)-2(2)}{3-2}=\frac{12-4}{1}=\frac{8}{1}=8$

∴ The coordinates fo point c are (-3 , -17 , 8)

* The position vector of point C is <-3 , -17 , 8> or -3i - 17j + 8k

3 0

3 years ago

ITS QUESTION 21 !!!!<br> Please help !

s2008m [1.1K]

He doesn't know where x is

7 0

3 years ago

Read 2 more answers