True or false? behavioral marketing and customer segmentation can help you rectify your mistakes and rebuild trust effectively

1 answer:

7 0

The statement which states that "behavioral marketing and customer segmentation can help you rectify your mistakes and rebuild trust effectively" is TRUE.

<h3>What is Customer Segmentation?</h3>

Customer segmentation can be defined as the process of classifying customers with common characteristics into groups based on the shared characteristics in other for a company to be able to effectively market or meet the needs of each market segment effectively.

Customer segmentation and behavioral marketing enable the company to understand the needs of a market and thereby build trust.

Therefore, the statement which states that "behavioral marketing and customer segmentation can help you rectify your mistakes and rebuild trust effectively" is TRUE.

Learn more about customer segmentation on: brainly.com/question/26872475

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What is the volume of this right prism? 96 in³ 60 in³ 48 in³ 44 in³

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Option C) 48in³ is the correct answer.

Hence, the volume of the right triangular prism is 48in³.

This question is incomplete, the missing diagram is uploaded along this answer.

Given the data in the question;

Side length a; $a = 4in$

Side length b; $b = 5in$

Side length c; $c = 3in$

Height; $h = 8in$

Volume; $V = \ ?$

<h3>Volume of right triangular Prism</h3>

Volume is simply the space created when a surface is enclosed , it is the space that a quantity material that can be held.

The volume of a right triangular prism can be expressed as;

$V = \frac{1}{4}h\sqrt{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}$

To determine the volume of the right triangular prism, we substitute our given values into the expression above.

$V = \frac{1}{4}h\sqrt{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}\\\\V = \frac{1}{4}*8in*\sqrt{(4in+5in+3in)(5in+3in-4in)(3in+4in-5in)(4in+5in-3in)}\\\\V = \frac{1}{4}*8in*\sqrt{(12in)(4in)(2in)(6in)}\\\\V = \frac{1}{4}*8in*\sqrt{576in^4}\\\\V = \frac{1}{4}*8in*24in^2\\\\V = \frac{1}{4} * 192in^3\\\\V = 48in^3$