Question

Factor completely 3x2 − 11x 8. (x 4)(3x − 2) (x − 2)(3x − 4) (x 1)(3x − 8) (x − 1)(3x − 8).

Answer 1

The factors of the equation $3x^{2} -11x+8$ will be $(3x-8)(x-1)$

What will be the factors of the given equation?

When we split the equation into two groups we will get

$3x^{2} -3x-8x+8$

$3x(x-1)-8(x-1)$

Now taking (x-1) common

$(3x-8)(x-1)$

Thus the factors of the equation $3x^{2} -11x+8$ will be $(3x-8)(x-1)$

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