Question

A cast iron pipe used as a water main for a home has an outer diameter of 8 in. If the pipe has a thickness of 0.6 in, what volume of iron does 29 in of pipe contain? Answer in cubic inches. Round your answer to the nearest hundredth if necessary. (Note: diagram is not drawn to scale.)

Answer 1

The volume of cast iron pipe is 1053.19 in³.

Volume of Cylinder

The volume of a cylinder can be calculated by: $\pi *r^2*h$, where:

r = radius

h= height

In this question, the cylinder is represented for a pipe, where:

r = inner diameter= $inner\;diameter=outer\;diameter-2*thickness$

h= length of pipe

From this, you should apply the volume of the pipe. See the steps:

• Step 1 - Find the inner diameter

         inner diameter=outer diameter-2*thickness

         inner diameter=8-2*0.6

         inner diameter=8-1.2=6.8 in              

• Step 2 - Find the volume of the pipe

                  $V_{pipe}=\pi *r_{internal}^2*h\\ \\ V_{pipe}=\pi *(\frac{6.8}{2} )^2*29\\ \\ V_{pipe}=\pi *(3.4)^2*29=1053.19\;in^3$

The volume of cast iron pipe is 1053.19 in³.

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