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3 years ago

Grampy $12 for 4 baseball packs James paid 28 for seven who got a better deal baseball card packs? And why

Mathematics

1 answer:

vitfil [10]3 years ago

7 0

Answer:

Grampy

Step-by-step explanation:

money cards

Grampy= $12 4 packs

James= $28 7 packs

12*2= 24 dollars and 8 packs

while James payed 28 dollars for 7 packs

So Grampy got a better deal.

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What is an equation of the line that passes through the point (-5 7) and is parallel to the line x-5y=15

mafiozo [28]

Answer:

Step-by-step explanation:

Parallel lines have same slope.

y = mx + b

Slope = m & y-intercept = b

x - 5y = 15

-5y = -x + 15

y = $\frac{-1}{-5}x + \frac{15}{-5}\\\\$

$y = \frac{1}{5}x - 3$

so, slope = 1/5 ; (-5 , 7)

y -y1 = m(x -x1)

$y - 7 = \frac{1}{5}(x- [-5])\\\\y - 7 =\frac{1}{5}(x + 5)\\\\y - 7 = \frac{1}{5}x+5*\frac{1}{5}\\\\y - 7 =\frac{1}{5}x+1\\\\y =\frac{1}{5}x+1+7\\\\y=\frac{1}{5}x + 8$

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3 years ago

Write an algebraic expression for the verbal description.

dimaraw [331]

Step-by-step explanation:

45X + 2000 = Y

Where X = Number of units

Y = Total Cost

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3 years ago

Jesse is not allowed to work more than 20 hours each week at his part time job . He has already worked 4 hours this week. The in

Drupady [299]

Been a bit since i’ve done this kind of problem.

X+4=20

X is the number of hours needed to work, while 4 is the hours already there.

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3 years ago

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How to find the correct unit of measurement? I am struggling with this. What is the difference between ft³, ft and ft²? Example:

arlik [135]

if you want to determine the perimeter / length, use a normal measure - ft.
The area is $ft^{2}$
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4 years ago

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Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

3 years ago