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laiz [17]
4 years ago
15

Which of the following best describes the change in the range when 13 is

Mathematics
1 answer:
svetoff [14.1K]4 years ago
6 0
The answer is D). It increases by 13.
If you put the numbers in order from least to greatest.. 26,34,38,49,65,75,81
You will see the 26 is the smallest number and 81 in the highest number. The range between the two numbers is 55. To find the range you take the smallest number and subtract it from the biggest number. But when you add the number 13 to the problem then26 is no longer the smallest Number because 13 replaced it. So then you take 81 and subtract 13 from it and get 68. And then you take 55 and subtract it from 68 and come with 13. Which makes the answer D.
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The average adult breathes in about 37L of air every 5 minutes. What is the rate of change of volume of air ?
galben [10]
37L/5 min. = 7.4 L/min.
8 0
3 years ago
In the figure below, EC || AB. Find the length of EC.
timofeeve [1]

Answer:

Letter a)

Step-by-step explanation:

quizlet

4 0
3 years ago
Read 2 more answers
Amy is pulling a wagon with a force of 30 pounds up a hill at an angle of 25°. Give the force exerted on the wagon as a vector a
Fofino [41]

Answer:

Vector (ordered pair - rectangular form)

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

Step-by-step explanation:

From statement we know that force exerted on the wagon has a magnitude of 30 pounds-force and an angle of 25° above the horizontal, which corresponds to the +x semiaxis, whereas the vertical is represented by the +y semiaxis.

The force (\vec F), in pounds-force, can be modelled in two forms:

Vector (ordered pair - rectangular form)

\vec F =  \left(\|\vec F\|\cdot \cos \theta, \|\vec F\|\cdot \sin \theta\right) (1)

Vector (ordered pair - polar form)

\vec F = \left(\|\vec F\|, \theta\right)

Sum of vectorial components (linear combination)

\vec {F} = \left(\|\vec F\|\cdot \cos \theta\right)\cdot \hat{i} + \left(\|\vec F\|\cdot \sin \theta \right)\cdot \hat{j} (2)

Where:

\|\vec F\| - Norm of the vector force, in newtons.

\theta - Direction of the vector force with regard to the horizontal, in sexagesimal degrees.

\hat{i}, \hat{j} - Orthogonal axes, no unit.

If we know that \|\vec F\| = 30\,lbf and \theta = 25^{\circ}, then the force exerted on the wagon is:

Vector (ordered pair - rectangular form)

\vec F= \left(30\cdot \cos 25^{\circ}, 30\cdot \sin 25^{\circ}\right)\,[lbf]

\vec F = (27.189,12.679)\,[lbf]

Vector (ordered pair - polar form)

\vec F = (30\,lbf, 25^{\circ})

Sum of vectorial components (linear combination)

\vec F = (30\cdot \cos 25^{\circ})\cdot \hat{i} + (30\cdot \sin 25^{\circ})\cdot \hat{j}\,[N]

\vec F = 27.189\cdot \hat{i} + 12.679\cdot \hat{j}\,[N]

8 0
3 years ago
Which search method employs the use of markers such as knots at regular intervals along the search line to indicate distance fro
vovangra [49]

The wide-area search method employs the use of markers such as knots at regular intervals along the search line.

Given the method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line.

In order to locate, relieve distress, and preserve the life of a person who has been reported missing or is believed to be lost, stranded, or is considered a high-risk missing person, wide area search and rescue refers to activities occurring within large geographic areas. It also refers to the removal of any survivors to a safe location.

Hence, the wide-area search method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line

Learn more about wide area from here brainly.com/question/15506214

#SPJ4

5 0
2 years ago
NEED HELP ASAP PLEASE!!
qwelly [4]

Option D:

$y=\frac{5x-2}{x}

Solution:

Given function:

$y=\frac{-2}{x-5}

To find the inverse of the function.

<u>Inverse of a function:</u>

<em>If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back to x.</em>

$y=\frac{-2}{x-5}

Interchange the variables x and y.

$x=\frac{-2}{y-5}

Now, solve for y.

Multiply both sides by (y - 5).

$x(y-5)=-\frac{2}{y-5}(y-5)

Cancel the common factors, we get

x(y-5)=-2

Divide by x on both sides.

$y-5=-\frac{2}{x}

Add 5 on both sides.

$y=-\frac{2}{x}+5

$y=-\frac{2}{x}+\frac{5}{1}

To make the denominator same, multiply the 2nd term by \frac{x}{x}.

$y=-\frac{2}{x}+\frac{5x}{x}

$y=\frac{-2+5x}{x}

$y=\frac{5x-2}{x}

Option D is the correct answer.

8 0
3 years ago
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