1) The graph
The corresponding graph shows a growing curve, its shape is kind of the right half of a parabola that opens upward and starts at the point (0, 2500).
The vertical axis corresponds to C(j), it contains divisions of 2500 units, and are marked 2500, 5000, 7500, 10000, 12500, 15000 and 17500.
The horizontal axis corresponds to j, and the marks are 75, 150, 225, 300, 375, and 450.
2) Domain
Domain is the set of possible values for the independent variable, which is placed on the horizontal axis. This is the possible values of j.
They are all the positive numbers and zero, the the domain is:
All real numbers, j, such that j ≥ 0
3) Range
Range is the set of possible images (dependent variable); this is the possible values of C(j).
As you can see on the graph C(j) ≥ 2500
Then, the range is [2500, ∞).
ANSWER:
As we know, diagonals of parallelogram (||gm) bisect each other.
So, AE = EC
2x - 10 = 8x - 70
2x - 8x = - 70 + 10
- 6x = - 60
x = 10
Answer:
C; Circle
Step-by-step explanation:
In this question, we are interested in giving a term to the locus of points which are at a certain distance from a fixed point.
The correct answer to this is a circle.
From the question, we can picture a situation which we have the point (1,2) as the center of the circle. This point serve the starting point in which all other points which are exactly 6 units away are plotted.
Thus, from this center point, we can mark off several points around the center point. By tracing the marked points from these center, we can obtain a circular path which when traced completely will give us the identity of a circle, where these points represent the line bounding the circle which is referred to the circumference of the particular circle in question.
Further more, from the definition of the radius of a circle, it is the distance from the center of a circle to the circumference. While the point (1,2) represents the center of the circle in question, the distance 6 units stand for the radius of the circle.
Answer:
Least possible value of b is 9.
Step-by-step explanation:
It is given that 
and b is an odd integer.
We need to find the least possible value of b.
We have,
Isolate variable terms.
Divide both sides by 3.
Since b>8 and b an odd integer, therefore the possible values of b are 9, 11, 13, 15, ... .
Hence, the least possible value of b is 9.
