The answer to this question is 8
Answer:
yes
Step-by-step explanation:
bc Quick maths
Not sure what you’re asking, but, if you’re looking for the expanded form... hope that helps?
The solution of the given equation represented in the task content can be determined by first evaluating the LCM and hence is; y= 27.
<h3>What is the solution of the equation as given in the task?</h3>
The given equation is; (y-5)/2=(y+6)/3.
Hence, by multiplying the equation by 6, we have;
3(y-5) = 2(y+6)
3y -15 = 2y +12
y = 27.
Hence, it follows that the value of y which is a solution to the equation is; y = 27.
Read more on equation solutions;
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<h2>
Speed of plane = 1110 kmph</h2><h2>
Speed of wind = 150 kmph</h2>
Step-by-step explanation:
Let the speed of plane be p and speed of wind be w.
Flying against the wind, an airplane travels 5760 kilometers in 6 hours.
Here
Speed = (p-w) kmph
Time = 6 hours
Distance = 5760 kmph
Distance = Speed x Time
5760 = (p-w) x 6
p-w = 960 -----eqn 1
Flying with the wind, the same plane travels 6300 kilometers in 5 hours.
Here
Speed = (p+w) kmph
Time = 5 hours
Distance = 6300 kmph
Distance = Speed x Time
6300 = (p+w) x 5
p+w = 1260 -----eqn 2
eqn 1 + eqn 2
p-w + p +w = 960 + 1260
2p = 2220
p = 1110 kmph
Substituting in eqn 2
1110 + w = 1260
w = 150 kmph
Speed of plane = 1110 kmph
Speed of wind = 150 kmph