All categories

3 years ago

What is the geometric mean of 9 and 18

Mathematics

1 answer:

klemol [59]3 years ago

5 0

$\cfrac{9}{x}~~ = ~~\cfrac{x}{18}\implies 162=x^2\implies \sqrt{162}=x\implies \sqrt{9^2\cdot 2}=x\implies 9\sqrt{2}=x$

You might be interested in

Whats 2099 dived by 800

sergejj [24]

Answer:

2099/800= 2.62375

Step-by-step explanation:

5 0

3 years ago

Use the diagram. What is the length of }EG ? A 1 B 4.4 C 10 D 16

nataly862011 [7]

Answer:

Option (D)

Step-by-step explanation:

Length of the bar EG = 1.6x

If F is a point on the bar such that,

EF + FG = EG

Measure of segment EF = 6

Measure of FG = x

By substituting measures of each side,

6 + x = 1.6x

1.6x - x = 6

0.6x = 6

x = 10

Length of EG = x + 6

= 10 + 6

= 16 units

Option (D) will be the correct option.

3 0

3 years ago

Suppose the average price for new cars in 2012 has a mean of $30,100 and a standard deviation of $5,600. Based on this informati

KatRina [158]

Answer:

($13,300,$46,900)

Step-by-step explanation:

We are given the following in he question:

Mean, μ = $30,100

Standard Deviation, σ = $5,600

Chebyshev's Theorem:

According to theorem atleast $1 - \dfrac{1}{k^2}$ percent of data lies within 2 standard deviations of mean.
For k = 3,

$1 -\dfrac{1}{(3)^2} = 0.889 \approx 89\%$

Thus, 89% of data lies within three standard deviation of mean.

$\mu - 3(\sigma) = 30100 - 3(5600) = 13300\\\mu + 3(\sigma) = 30100 + 3(5600) = 46900$

Thus, we expect at least 89% of new car prices to fall within ($13,300,$46,900)

3 0

3 years ago

-2x + 3x - 5 = 6 - 21 FIND x

trasher [3.6K]

Before we do any solving, we need to simplify both sides.

On the left, we can simplify -2x + 3x - 5 to x - 5.

On the right, we can simplify 6 - 21 to -16.

So we have x - 5 = -16.

Solving from here, we add 5 to both sides to get x = -11.

5 0

3 years ago

Multiple polynomial the (x^3+3x^2+1)(3x^2+6x-2)

Mrrafil [7]

The product of given polynomials is: $3x^5+15x^4-16x^3-3x^2+6x-2$

Step-by-step explanation:

Given polynomials are:

$(x^3+3x^2+1)\\and\\(3x^2+6x-2)$

In order to multiply both polynomials, we will use the distributive property

So,

$= (x^3+3x^2+1)(3x^2+6x-2)\\=x^3(3x^2+6x-2)+3x^2(3x^2+6x-2)+1(3x^2+6x-2)\\=3x^5+6x^4-2x^3+9x^4+18x^3-6x^2+3x^2+6x-2$

Combining like terms

$=3x^5+6x^4+9x^4-2x^3+18x^3+3x^2-6x^2+6x-2\\=3x^5+15x^4-16x^3-3x^2+6x-2$

Hence,

The product of given polynomials is: $3x^5+15x^4-16x^3-3x^2+6x-2$

Keywords: Polynomials, variables

Learn more about polynomials at:

#LearnwithBrainly

6 0

4 years ago