Answer:
Risk management is the technique that is used for managing the risky situation so that security of the system or organization can be maintained. The risk can be reduced by parameters like monitoring the system,alertness, preventive measures etc. There are terms related with the risk management for prevention of the risk such as risk control ,risk identification and risk assessment .
- Risk control is the method that is used for calculating the loss or damage experience and then taking the correct measures to reduce the loss and thus, controlling the risk.
- Risk assessment is the analyzation of the threats and source of damage/loss that is caused or can be caused by assessing the whole process and functioning.
- Risk identification is the technique through which the threat is listed over a document and sorted in accordance with the category of risk, risk response etc.
Hard to see please add a better image. Actually just type out the question.
Answer:
cout << setprecision(2)<< fixed << number;
Explanation:
The above statement returns 12.35 as output
Though, the statement can be split to multiple statements; but the question requires the use of a cout statement.
The statement starts by setting precision to 2 using setprecision(2)
This is immediately followed by the fixed manipulator;
The essence of the fixed manipulator is to ensure that the number returns 2 digits after the decimal point;
Using only setprecision(2) in the cout statement will on return the 2 digits (12) before the decimal point.
The fixed manipulator is then followed by the variable to be printed.
See code snippet below
<em>#include <iostream> </em>
<em>#include <iomanip>
</em>
<em>using namespace std; </em>
<em>int main() </em>
<em>{ </em>
<em> // Initializing the double value</em>
<em> double number = 12.3456; </em>
<em> //Print result</em>
<em> cout << setprecision(2)<< fixed << number; </em>
<em> return 0; </em>
<em>} </em>
<em />
I guess the correct answer is application
An applicatiοn layеr is an abstractiοn layеr that spеcifiеs thе sharеd cοmmunicatiοns prοtοcοls and intеrfacе mеthοds usеd by hοsts in a cοmmunicatiοns nеtwοrk. Thе applicatiοn layеr abstractiοn is usеd in bοth οf thе standard mοdеls οf cοmputеr nеtwοrking: thе Intеrnеt Prοtοcοl Suitе (TCP/IP) and thе ΟSI mοdеl. Althοugh bοth mοdеls usе thе samе tеrm fοr thеir rеspеctivе highеst lеvеl layеr, thе dеtailеd dеfinitiοns and purpοsеs arе diffеrеnt.
Answer:
Question is incomplete. it needs a topology diagram and also it needs Router R1 table. I assume User has access to the topology and Routing table.
Below Configuration will help to fix ACL problem
Hosts from the 172.16.0.0/16 network should have full access to Server1, Server2 and Server3 but this is not currently the case, as L1 can’t communicate to Server2 or Server3.
Explanation:
Following Configuration on Cisco Router R1 will help to fix all the ACL problems.
enable
configure terminal
no ip access-list standard FROM_10
ip access-list standard FROM_10
deny host 10.0.0.2
permit any
exit
!
no ip access-list standard FROM_172
ip access-list standard FROM_172
permit host 172.16.0.2
exit
!
interface GigabitEthernet0/0
ip access-group FROM_192 out
end
write memory
!