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lapo4ka [179]
3 years ago
5

Why does earth exert the same impulse during the two time intervals in problem 10 but different impulses during the same distanc

es traveled in problem 11
Physics
1 answer:
Gekata [30.6K]3 years ago
6 0

The possible cause of difference in impulse is the change in momentum of the objects in the two problems.

<h3>What is impulse?</h3>

Impulse is effect produced by applied forces. Impulse is the product of force and time of action.

J = Ft

<h3>Change in momentum</h3>

Impulse is the change in momentum of an object.

J = ΔP

where;

ΔP is change in momentum

Thus, the possible cause of difference in impulse is the change in momentum of the objects in the two problems.

Learn more about impulse here: brainly.com/question/25700778

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A schoolbus accelerates to 65 mph and enters the freeway. It travels for 2.3 hours at that speed while on the freeway. What's th
PtichkaEL [24]

Answer:

The distance travelled on the freeway is 149.5 miles.

Explanation:

The school bus travels on the freeway at constant speed. According to the statement, we need to calculate the distance travelled by the vehicle by means of the following formula:

x = v\cdot t (1)

Where:

x - Traveled distance, in miles.

v - Speed, in miles per hour.

t - Time, in hours.

If we know that v = 65\,\frac{mi}{h} and t = 2.3\,h, then the distance travelled by the school bus is:

x = v\cdot t

x =  \left(65\,\frac{mi}{h} \right)\cdot (2.3\,h)

x = 149.5\,mi

The distance travelled on the freeway is 149.5 miles.

5 0
3 years ago
What is the abbreviation for mojave desert?
vagabundo [1.1K]
There is no abbreviation
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3 years ago
A cat dozes on a stationary merry-go-round, at a radius of 5.7 m from the center of the ride. Then the operator turns on the rid
tatyana61 [14]

Answer:

0.76

Explanation:

we are given:

radius (r) =5.7 m

speed (s) = 1 revolution in 5.5 seconds

acceleration due to gravity (g) = 9.8 m/s^{2}

coefficient of friction (Uk) = ?

 we can get the minimum coefficient of friction from the equation below

centrifugal force = frictional force

m x r x ω^{2} = Uk x m x g

r x ω^{2} = Uk x g

Uk = \frac{ r x ω^{2} }{g}

where ω (angular velocity) = \frac{2π}{time}

= \frac{2π }{5.5} = 1.14

Uk = \frac{ 5.7 x 1.14^{2} }{9.8} = 0.76

6 0
3 years ago
2. In the pendulum lab, the period (swing time) was O a. the independent variable O b.graphed on the vertical-axis O c.graphed o
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B is appropriate answer
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3 years ago
You push very hard on a heavy desk, trying to move it. You do work on the desk:
frozen [14]

Answer:

(C) Only if it starts moving

Explanation:

We know that work done is given by

W=F.d=Fdcos\Theta

So there are two case in which work done is zero

First case is that when force and displacement are perpendicular to each other

And other case is that when there is no displacement

So for work to be done there must have displacement, if there is no displacement then there is no work done

So option (c) will be the correct option

3 0
3 years ago
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