A standing wave on a string that is fixed at both ends has frequency 80.0 Hz. The distance between adjacent antinodes of the sta
1 answer:
Answer:
v = 19.2 m/s
Explanation:
In order to find the speed of the string you use the following formula:
(1)
f: frequency of the string = 80.0Hz
v: speed of the wave = ?
L: length of the string = 12.0cm = 0.12m
The length of the string coincides with the wavelength of the wave for the fundamental mode.
Then, you solve for v in the equation (1), and replace the values of the other parameters:
The speed of the wave is 19.2 m/s
You might be interested in
Answer:
The correct option is: B that is 1/2 K
Explanation:
Given:
Two carts of different masses, same force were applied for same duration of time.
Mass of the lighter cart =
Mass of the heavier cart =
We have to find the relationship between their kinetic energy:
Let the KE of cart having mass m be "K".
and KE of cart having mass m be "K1".
As it is given regarding Force and time so we have to bring in picture the concept of momentum Δp and find a relation with KE.
Numerical analysis.
⇒
⇒
⇒
⇒
⇒
⇒
Now,
Kinetic energies and their ratios in terms of momentum or impulse.
KE (K) of mass m.
⇒ ...equation (i)
KE (K1) of mass 2m.
⇒
⇒ ...equation (ii)
Lets divide K1 and K to find the relationship between the two carts's KE.
⇒
⇒
⇒
⇒
⇒
⇒
The kinetic energy of the heavy cart after the push compared to the kinetic energy of the light cart is 1/2 K.