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Ksenya-84 [330]
2 years ago
8

26 POINTS!! will give brailest! can anyone help me? if you can't well, Merry Christmas!

Physics
1 answer:
Korolek [52]2 years ago
5 0

Have an amazing day you are an amazing person:)

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Is more of north america north or south of the tropic of cancer
TEA [102]

Explanation:

This parallel is located in the northern hemisphere, located at a latitude of 23 ° 26′12.2 ″ (or 23,43671 °) north of the equator. Approximately in the geographic half of Mexico, crossing the states of Baja California Sur, Sinaloa, Durango, Zacatecas, San Luis, Potosí, Nuevo León, Tamaulipas. Therefore, there is more of north america, at north of the tropic of cancer.

6 0
2 years ago
If the 50 kg objects slows down to a velocity of 1 m/s how much kinetic energy does it have?
Bogdan [553]

It has 50kg with a velocity of 1 m/s times the speed of the cart divided by 2 and multiplied by kinectic x plus 5

3 0
3 years ago
Read 2 more answers
In a nuclear physics experiment, a proton (mass 1.67×10^(−27)kg, charge +e=+1.60×10^(−19)C) is fired directly at a target nucleu
Arte-miy333 [17]

The given question is incomplete. The complete question is as follows.

In a nuclear physics experiment, a proton (mass 1.67 \times 10^(-27)kg, charge +e = +1.60 \times 10^(-19) C) is fired directly at a target nucleus of unknown charge. (You can treat both objects as point charges, and assume that the nucleus remains at rest.) When it is far from its target, the proton has speed 2.50 \times 10^6 m/s. The proton comes momentarily to rest at a distance 5.31 \times 10^(-13) m from the center of the target nucleus, then flies back in the direction from which it came. What is the electric potential energy of the proton and nucleus when they are 5.31 \times 10^{-13} m apart?

Explanation:

The given data is as follows.

Mass of proton = 1.67 \times 10^{-27} kg

Charge of proton = 1.6 \times 10^{-19} C

Speed of proton = 2.50 \times 10^{6} m/s

Distance traveled = 5.31 \times 10^{-13} m

We will calculate the electric potential energy of the proton and the nucleus by conservation of energy as follows.

  (K.E + P.E)_{initial} = (K.E + P.E)_{final}

 (\frac{1}{2} m_{p}v^{2}_{p}) = (\frac{kq_{p}q_{t}}{r} + 0)

where,    \frac{kq_{p}q_{t}}{r} = U = Electric potential energy

     U = (\frac{1}{2}m_{p}v^{2}_{p})

Putting the given values into the above formula as follows.

        U = (\frac{1}{2}m_{p}v^{2}_{p})

            = (\frac{1}{2} \times 1.67 \times 10^{-27} \times (2.5 \times 10^{6})^{2})

            = 5.218 \times 10^{-15} J

Therefore, we can conclude that the electric potential energy of the proton and nucleus is 5.218 \times 10^{-15} J.

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3 years ago
If you go to the beach and get a cup of water out of the ocean, does the water in the cup have the same average kinetic energy a
DiKsa [7]
Yes, the water in the cup have the same average kinetic energy as the ocean, because I focus on the word 'average'. However the cup of water have less INTERNAL energy than the ocean.
hope it helps☺☺
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The contour interval of a topographic map is 25 feet. How many contour lines will be drawn between sea level and an elevation of
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