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Arisa [49]
2 years ago
13

3 lbs, 7 ounces = ____ ounces

Mathematics
2 answers:
Dafna1 [17]2 years ago
5 0

Answer:

one pound is equal to 16 oz

(3x16= 48)

(48+7=55)

55 ounces

natima [27]2 years ago
3 0
55 ounces


hope this helpssssss
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solve each linear-quadratic system graphically. if necessary, round to the nearest integer. please show work
GenaCL600 [577]

Answer:

thx sa points

Step-by-step explanation:

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2 years ago
Nate has $50 to spend at the grocery store. He fills his shopping cart with items totaling $46. At checkout he will have to pay
Deffense [45]

Answer:

yes

Step-by-step explanation:

Find the amount of the sales tax:

46 x 0.06 = 2.76

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3 years ago
What number increased by 3,080 equals 5,082?
kodGreya [7K]
Let the required number be x, then
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3 years ago
I give ten points and brainliest if you say hi
patriot [66]

Answer:

Hi hope you have a wonderful and blessed day!!!!

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
According to an​ airline, flights on a certain route are on time 80 ​% of the time. suppose 10 flights are randomly selected and
natulia [17]
<span>(a) This is a binomial experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
​(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
​(c) Fewer than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
​(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
</span>
6 0
2 years ago
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