Answer:
The critical points are 12 and 0.
Step-by-step explanation:
We have that the critical numbers are those values that result from equating the derivative of a function to zero. Also called roots or zeros of the derived function.
IF f is defined in x, it will be said that a is a critical number of f if f '(x) = 0 or if f is not defined in x.
Now the function is:
f (x) = x ^ 2 / (x -6)
we have that the derivative of the quotient is:
(f / g) '= (f' * g - g '* f) / g ^ 2
we replace and we have:
f (x) = [2 * x * (x-6) - 1 * x ^ 2] / (x -6) ^ 2
simplifying we have:
f (x) = [x ^ 2 - 12 * x] / (x -6) ^ 2
this must be equal to 0, like this:
[x ^ 2 - 12 * x] / (x -6) ^ 2 = 0
we solve:
x ^ 2 - 12 * x = 0
x * (x - 12) = 0
Thus:
x = 0
x - 12 = 0 => x = 12
The critical points are 12 and 0.
