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Semmy [17]
3 years ago
7

560 cars in 8 hours.how many cars per hour?​

Mathematics
2 answers:
zepelin [54]3 years ago
7 0

Answer:

70

Step-by-step explanation:

so i uhhhh dont really know im trying to cheat but i cant see answers

alexandr402 [8]3 years ago
7 0

Answer:

\huge\boxed{70 _\frac{\text{cars}}{\text{hour}} }

Step-by-step explanation:

This problem requires you to find the unit rate.  The unit rate is the number of something in exactly <u>1</u> of another.

Simply divide 560 by 8 to get the unit rate in this problem.

560 / 8 = 70

Hope it helps :) and let me know if you want me to elaborate.

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Which is an outlier out of 45,47,71,50,49 and 52
Elis [28]

The outlier is 71.

An outlier in a set of data is the one that is significantly lower or higher than the average of the totals. Whichever number skews the average is the outlier.

In this case, it's 71.

:)

6 0
4 years ago
Tristan is working two summer jobs, making $7 per hour babysitting and $19 per hour lifeguarding. Tristan must earn at least $21
rodikova [14]

Answer: 7bb +19 ll ≥210

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

The product of the number of hours he works babysitting (bb) and the amount he earns per hour (7); plus The product of the number of hours he works lifeguarding (ll) and the amount he earns per hour 19; must be higher or equal to the amount he must earn this week (210)

Mathematically speaking:

7 bb + 19 ll ≥210

6 0
3 years ago
What is the d stand for????
SOVA2 [1]

Answer:

The missing variable

Step-by-step explanation:

D=2

5 0
3 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
Mica bought a new smart phone for $258.13. That was the price after his 18.25% discount. What was the original price of the phon
julia-pushkina [17]

The original price of phone is $ 315.76

<em><u>Solution:</u></em>

Given that Mica bought a new smart phone for $ 258.13.

That was the price after his 18.25% discount

<em><u>To find: original price of phone</u></em>

From given question,

price after discount = $ 258.13

discount = 18.25 %

Let "x" be the original price of phone

price after discount = original price - discount

258.13 = x - 18.25 \% \text{ of } x

258.13 = x - \frac{18.25}{100}x

258.13 = x(1 - \frac{18.25}{100})

258.13 = x(1 - 0.1825)\\\\258.13 = x( 0.8175)\\\\x = \frac{258.13}{0.8175}\\\\x = 315.76

Thus original price of phone is $ 315.76

4 0
4 years ago
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