Answer:
No.
Step-by-step explanation:
In order to complete the square, you need to have the x values together, not the constant.
To complete the square <em>correctly </em>you would need to have x² - 20x = -6 and continue from there; divide 20 by 2 and square the result to get (x - 10)² = 96.
Answer:
1. 32
2. 24
3. 
4. 
5. 15
6. 
Step-by-step explanation:
1. 4÷ 
2. 6÷
3.
÷4=
4.
÷4=
5. 5÷
6.
÷5=
Answer:
a random sample of size 5 from a population that is approximately normal
a random sample of size 60 from a population that is strongly skewed to the left.
Step-by-step explanation:
They are both correct
4(4/5) + √(4/5) + 0.2 - 5(4/5)
= 16/5 + (2√5/5) + (1/5) - 4
= (16 + 2√5 + 1 - 20)/5
= (2√5 - 3)/5 or 0.29442719
(a) Using Newton's Law of Cooling,

, we have

where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get

. Integrate both sides to get

.
Since

, we solve for C:

So we get

. Use T(30) = 150 to solve for k:

So

But choose Positive because T > 75. Temp of turkey can't go under.

(b)

Dogs of the AMS.