For the second line
The intersection will be
Therefore, the point of intersection is (13, 16)
Your answer is 110.6. If T remains constant with R, then divide R by 5, then multiply it by 7, then you have ur answer 110.6. Hope this helped!
Thanks!
~Steve
Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:
length=20/4=5 cm
the ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:
AC=4x and BD=3x
using Pythagorean theorem, the length of one side of the rhombus will be:
c^2=a^2+b^2
substituting our values we get:
5²=(2x)²+(1.5x)²
25=4x²+2.25x²
25=6.25x²
x²=4
x=2
hence the length of the diagonals will be:
AC=4x=4×2=8 cm
BD=3x=3×2=6 cm
Hence the area of the rhombus wll be:
Area=1/2(AC×BD)
=1/2×8×6
=24 cm²
3
The period is the amount it time it takes to make one complete cycle. If we start at 0 for simplicity sake, the graph is at its maximum point. It reaches its maximum point again at 3, this is one complete cycle and thus the period is 3.
Answer:
10/9
Step-by-step explanation:
Step-by-step explanation:
5 • 2/9 = 10/9
Multiply 5 and 2
