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bekas [8.4K]
3 years ago
15

K=3yz solve for y algebra 1

Mathematics
1 answer:
RideAnS [48]3 years ago
7 0
Answer is : y = k / 3z
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Help me and ill give brainlist
Cerrena [4.2K]

3 X 10 = 30/2 = 15

area: 15yd^2

3 0
2 years ago
Read 2 more answers
What type of polynomial is this and what is its degree?<br> 5b3 - 3 + 6b
Dmitry_Shevchenko [17]

Answer:

3rd degree trinomial

Step-by-step explanation:

the highest power is 3 and there are 3 terms so its a 3rd degree trinomial

3 0
2 years ago
YOU CAN EARN YOURSEL A BRAINLEST! (0.&lt;)
Gelneren [198K]

Answer:    

P(x) = 0.50x - 5

Step-by-step explanation:

x = number of glasses sold

She charges $0.50 per glass, so her revenue is

R(x) = 0.50x

which is the amount of money she brings in

Her cost function is

C(x) = 5

assuming she only spends that $5.00 on the supplies mentioned.

The profit P(x) is the difference of revenue and cost

Profit = Revenue - Cost

P(x) = R(x) - C(x)

P(x) = 0.50x - 5

4 0
2 years ago
Components of a certain type are shipped to a supplier in batches of ten. suppose that 50% of all such batches con- tain no defe
dimulka [17.4K]
Solution
Let 0 be the event that the batch has 0 defectives, 1 be the event the batch has 1 defective, and 2 be
the event the batch has 2 defectives. Let 0 be the event that neither selected component is defective.
(0
) = 0.5,(1
) = 0.3, (2
) = 0.2
The event 0 can happen in three different ways: (i) Our batch of 10 is perfect, and we get no defectives in
our sample of two; (ii) Our batch of 10 has 1 defective, but our sample of two misses them; (iii) Our batch
has 2 defective, but our sample misses them.
For (i), the probability is (0.5)(1).
For (ii), the probability that our batch has 1 defective is 0.3. Given that it has 1 defective, the probability
that our sample misses it is (
9
2
)
(
10
2
)
, which is 8
10
. So the probability of (ii) is (0.3) (
8
10).
For (iii), the probability our batch has 2 defective is 0.2. Given that it has 2 defective, the probability that
our sample misses both is (
8
2
)
(
10
2
)
, which is 56
90
. So the probability of (iii) is (0.2) (
56
90). We have therefore found
that
(0
) = (0.5)(1) + (0.3) (
8
10) + (0.2) (
56
90).
We use the general conditional probability formula:
(0
|0
) =
(0 ∩ 0
)
(0
)
=
(0.5)(1)
(0.5)(1) + (0.3) (
8
10) + (0.2) (
56
90)
= 0.5784.
(1
|0
) =
(1∩0
)
(0
)
=
(0.3)(
8
10)
(0.5)(1)+(0.3)(
8
10)+(0.2)(
56
90)
= 0.2776.
(2
|0
) =
(2∩0
)
(0
)
=
(0.2)(
56
90)
(0.5)(1)+(0.3)(
8
10)+(0.2)(
56
90)
= 0.1440.
Answer: 0.5784; 0.2776; 0.1440.
4 0
3 years ago
Which graph represents a function?
natulia [17]
You'd want to use a vertical line test.

1st image: Every vertical line cuts the graph at at most one point
2nd image: The vertical line x = 1 cuts the graph at more than one point
3rd image: The vertical line x = 1 cuts the graph at 2 points
4th image: The vertical line x = -2 cuts the graph at 2 points

Hence, graph 1 (1st image) is a function.
6 0
3 years ago
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