You would multiply the like (or similar) terms together.
2*4= 8
-5i*7i= -35i
The correct answer is "A".
I hope this helped you.
Brainliest answer is always appreciated.
This is pretty simple. All you have to do is make the first and second fraction share a denominator by multiplying them by each other.
6 <span>• 9 = 54
Then multiply each numerator by the opposing denominator.
1 </span><span>• 9 = 9
2 </span><span>• 6 = 12
Here are the new fractions:
9/54
12/54
Now add the 9 and 12 together.
9 + 12 = 21
The complete fraction:
21/54
Subtract 21 from 54 so you can get the remainder of the sweater.
54 - 21 = 33
This is the remainder fraction:
33/54
Can you simplify this? Yes, of course! They can both be divided by 3!
11/18
That is the remainder of the sweater. But you still have to divide it in half! After all, Linda only knitted half of the remaining sweater. Dividing it in half can be done just by multiplying the denominator by 2.
11/36
That should be your answer! Apologies if I got something wrong.</span>
Answer:
31.25 k
Step-by-step explanation:
80 % * x = 25 k
.80 x = 25 k
x = 25 k / .80 = 31.25 k
The error to that problem is the person switched the x and y points, like in point A, it’s supposed to be (x,y) or (1,5). The person put the y in front of the x while writing the points.
Answer:

Step-by-step explanation:
You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.
You will find when you look on your trig identity sheet that

so we will make that replacement, getting everything in terms of sin:

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

We can factor out the sin(theta), since it's common in both terms:

Because of the Zero Product Property, either
or

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

The next equation needs to first be solved for sin(theta):
so
and

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:
