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Oxana [17]
4 years ago
15

Compute the simple interest earned on a deposit of $5000 at 8.5% for 120 days

Mathematics
1 answer:
ICE Princess25 [194]4 years ago
4 0
Keeping in mind that 120 days is not even a year, since there are 365 days in a year, exluding leap-years, then 120 days is really 120/365 year.

\bf ~~~~~~ \textit{Simple Interest Earned}
\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$5000\\
r=rate\to 8.5\%\to \frac{8.5}{100}\to &0.085\\
t=years\to \frac{120}{365}\to &\frac{24}{73}
\end{cases}
\\\\\\
I=(5000)(0.085)\left( \frac{24}{73} \right)\implies I \approx 139.72602739726
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Create a polynomial that is added to 5x2 + 6x + 9 to get 7x2 + 9x + 14.
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Answer:

Step-by-step explanation:

Subtract first from second

= 2x^2 + 3x + 5

4 0
3 years ago
give an example of addition problem in which you would and would not group the addends differently to add
aleksandrvk [35]
An <u>example of a problem</u> where I <em>would not</em> group the addends differently is:

3+2+4.

An <u>example of a problem</u> where I <em>would</em> group the addends differently is:

2+5+8.

Explanation:

In the <u>first problem</u>, I would not group the addends differently before adding.  This is because I cannot make 5 or 10 out of any of the numbers.  We group addends together to make "easier" numbers for us to add, such as 5 and 10.  If we cannot do that, there is no reason to regroup the addends.

In the <u>second problem</u>, I would regroup like this:
2+8+5

This is because 2+8=10, which makes the problem "easier" for us to add.  Since we can get a number like this that shortens the process, we can regroup the addends.
3 0
3 years ago
Read 2 more answers
PLEASE HELP! WILL GIVE BRAINLIEST! After substituting, what is the first step when evaluating 4y+9 when y=82 O Add 4 and 9. O Mu
Svetradugi [14.3K]

Answer:

The answer is c

Step-by-step explanation:

3 0
3 years ago
P(x)=5x^2-3x+7(x=1)<br> Pls
kramer

Answer:

9

Step-by-step explanation:

Given

p(x) = 5x² - 3x + 7 ← substitute x = 1

p(1) = 5(1)² - 3(1) + 7 = 5(1) - 3(1) + 7 = 5 - 3 + 7 = 9

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3 years ago
Gianna invested $30,000 in an account paying an interest rate of 1.9% compounded
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5,095,068

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The equation for this problem is x^y * z where x is the percentage, Y is the number of years, and Z is the original deposit. Multiply 1.9^8 * 30,000 which becomes; 5,095,068.

Whoever has that bank account is going to be very rich.

3 0
4 years ago
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