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Oxana [17]
4 years ago
15

Compute the simple interest earned on a deposit of $5000 at 8.5% for 120 days

Mathematics
1 answer:
ICE Princess25 [194]4 years ago
4 0
Keeping in mind that 120 days is not even a year, since there are 365 days in a year, exluding leap-years, then 120 days is really 120/365 year.

\bf ~~~~~~ \textit{Simple Interest Earned}
\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$5000\\
r=rate\to 8.5\%\to \frac{8.5}{100}\to &0.085\\
t=years\to \frac{120}{365}\to &\frac{24}{73}
\end{cases}
\\\\\\
I=(5000)(0.085)\left( \frac{24}{73} \right)\implies I \approx 139.72602739726
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3 years ago
Lin ran 2 3/4 miles in 2/5 of an hour, Noah ran 8 2/3 miles in 4/3 of an hour, how far would Lin run in 1 hour?
Marizza181 [45]

Answer:

6\frac{7}{8}\ miles

Step-by-step explanation:

Given that Lil's distance in 2/5 hrs is 2 3/4hrs

-Let x be the distance ran in 1 hr.

#We equate and cross multiply to solve for x as follows:

\frac{2}{5}\ hrs=2\frac{3}{4}\\1\ hr=x\\\\\therefore x=2\frac{3}{4}/\frac{2}{5}\\\\=6\frac{7}{8}\ miles

Hence, Lil can run 6 7/8 miles in 1 hr.

5 0
3 years ago
Write the equation g(x) in vertex form of a
DerKrebs [107]

The equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Given a  quadratic function for the transformations given  the function f(x) = x²

If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value

  • Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)

Hence the equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Learn more here: brainly.com/question/15381183

8 0
3 years ago
Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do
const2013 [10]

Answer:

y_p=A+Bt+Ce^{2t}

Step-by-step explanation:

Given: y'' - 2y' = 6t + 5e^{2t}.

we need to find the correct form for y_p if the equation is solve using undetermined coefficients.

A first order differential equation \frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right ) is said to be homogeneous if f(tx,ty)=f(x,y) for all t.

Consider homogeneous equation y''-2y'=0

Let y=e^{rt} be the solution .

We get (r^2-2r)e^{rt}=0

Since e^{rt}\neq 0, r^2-2r=0.

So, we get solution as y_c=c_1+c_2e^{2t}

As constant term and e^{2t} are already in the R.H.S of equation

y" - 2y' = 6t + 5e^{2t}, we can take y_p as y_p=A+Bt+Ce^{2t}

6 0
4 years ago
The cost of five books is 71 dollars what is the cost of each book
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Divide 71 and 5 to get a decimal since 71 does not end with 5 or 0. Do it to get 14 1/5 or 14.2
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3 years ago
Read 2 more answers
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