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3 years ago

Compute the simple interest earned on a deposit of $5000 at 8.5% for 120 days

1 answer:

4 0

Keeping in mind that 120 days is not even a year, since there are 365 days in a year, exluding leap-years, then 120 days is really 120/365 year.

$\bf ~~~~~~ \textit{Simple Interest Earned}
\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$5000\\
r=rate\to 8.5\%\to \frac{8.5}{100}\to &0.085\\
t=years\to \frac{120}{365}\to &\frac{24}{73}
\end{cases}
\\\\\\
I=(5000)(0.085)\left( \frac{24}{73} \right)\implies I \approx 139.72602739726$

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Felicity's dog eats no more than two cups of dog food per day. Felicity's dog eats at least one-quarter cup more than one-half o

horrorfan [7]

Answer:

$\frac{1}{4}+\frac{m}{2} \leq x\leq 2$

$x$ denotes amount of food that Felicity's dog eats

Step-by-step explanation:

Given:

Felicity's dog eats no more than two cups of dog food per day.

Felicity's dog eats at least one-quarter cup more than one-half of the amount Martin's dog eats.

The amount of food that Martin's dog eats is represented by using $m$

To find: the inequality that represents the situation

Solution:

Amount of food that Martin's dog eats = $m$

Amount of food that Felicity's dog eats ≤ 2

Also,

Amount of food that Felicity's dog eats $\geq \frac{1}{4}+\frac{m}{2}$

Therefore,

$\frac{1}{4}+\frac{m}{2}\leq$ Amount of food that Felicity's dog eats ≤ 2

Let $x$ denotes amount of food that Felicity's dog eats.

$\frac{1}{4}+\frac{m}{2}$ ≤ $\frac{1}{4}+\frac{m}{2} \leq x\leq 2$

3 0

3 years ago

Simplify the product (x-4)(x+3)

Kamila [148]

Answer:

Final answer is $x^2-x-12$ .

Step-by-step explanation:

Given expression is $\left(x-4\right)\left(x+3\right)$ .

Now we need to find the product of the given expression $\left(x-4\right)\left(x+3\right)$ .

$\left(x-4\right)\left(x+3\right)$

$=x\left(x-4\right)+3\left(x-4\right)$

$=x^2-4x+3x-12$

combine like terms

$=x^2-1x-12$

$=x^2-x-12$

Hence final answer is $x^2-x-12$ .

7 0

3 years ago

Read 2 more answers

I want to know the work of this, like the process. Please

pogonyaev

In this question, you know that the machine packs $\frac{2}{3}$ of a box every $\frac{1}{2}$ of a minute. Since it is constant, you simply have to double the half a minute to a full minute and then also double the rate to get $\frac{4}{3}$ boxes packed per minute. And $\frac{4}{3}$ is equal to $1\frac{1}{3}$