8x+3=43
-3 -3
8x=40
/8 /8
X=5
<h2>
Answer:</h2>
<h2>
Step-by-step explanation:</h2>
The question in this problem is:
<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>
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First of all, let's name the first variable which is the smaller number. Accordingly, the lager number will be given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:
So:
1. The sum of 2 consecutive integers can be written as:
2. Nine times the smaller and 5 times the larger can be written as:
Finally, the whole statement:
The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:
The two numbers are:
Answer:
Step-by-step explanation:
We would assume a binomial distribution for the handedness of the population. Let x be a random variable representing the type of handedness in the population. The probability of success, p is that a randomly chosen person is left handed only. Then probability of failure is that a chosen person is not left handed only(right handed only or both).
p = 12/100 = 0.12
number of success, x = 20
n = 200
the probability that there are at least 20 left-handers is expressed as P(x ≥ 20)
From the binomial probability calculator,
P(x ≥ 20) = 0.84
Answer:l
l
Step-by-step explanation:
N=5
solve it the same way you would a proportion