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Lerok [7]
3 years ago
8

Jack’s sister is coming to visit him and parks in the hospital car park. The bar chart below shows some information about the ca

rs parked in the car park. How many more white than silver cars are parked in the hospital car park?
Mathematics
1 answer:
ziro4ka [17]3 years ago
3 0
I need the chart to finish it you'll have to post it

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A square has a side length of 9 feet. What is the area of the square
oee [108]

Answer:

81

Step-by-step explanation:

The area of a square is its side length squared so 9^2 is 81

4 0
3 years ago
Five times the difference of a number and 12 minus 4 times the same number is – 36. What is the equation?
Katen [24]

Answer:

(5x - 12) - 4x = -36

Step-by-step explanation:

8 0
3 years ago
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Please help asap! Will give brainliest! Please read the question then answer correctly! No guessing.
frutty [35]

Answer:

(x - 5) (x - 7)

Step-by-step explanation:

<em><u>To factor this trinomial, you must split the middle term (-12x) into two terms that can be added to get -12x, and multiplied to get 35:</u></em>

<em><u /></em>x^2 - 12x + 35

x^2 -7x - 5x + 35

<em><u>Group:</u></em>

(x^2 -7x) (-5x + 35)

<em><u>Take out the GCF (Greatest Common Factor):</u></em>

x(x - 7)  -5(x - 7)

(x - 5) (x - 7)

4 0
3 years ago
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Guys what is the log2(56/9)<br> Pls pls pls pls help
Charra [1.4K]
Answer:
3+log2(7/9)
Explanation:
8 0
3 years ago
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Your lungs hold about 4.5 liters of air after you inhale and about 3.5 liters of air after you exhale. If you take 6 breaths eve
ser-zykov [4K]

Answer:

A(t)=0.5cos(12\pi\cdot t)+4

Step-by-step explanation:

<u>Function Modeling</u>

Since the air in the lungs goes periodically from a minimum value to a maximum value, we can simulate its behavior as a sinusoid. Selecting a sine or a cosine will depend on the initial condition we'll assume since the question doesn't provide one. We'll set the initial state when the lungs are at maximum air content. The sinusoid that starts from maximum is the cosine, so our model is

A(t)=A_ocos(wt)+M

Where Ao is the amplitude of the oscillation, w is the angular frequency and M is the midline or y-displacement of the wave.

The values of A run from a min of 3.5 to a max of 4.5. That gives us twice the amplitude, thus

\displaystyle A_o=\frac{4.5-3.5}{2}=0.5

The vertical displacement or midline can be found as the shift from the center value:

\displaystyle M=\frac{4.5+3.5}{2}=4

We also know the cycle repeats 6 times per minute. If the time is expressed in minutes, then the frequency is f=6

Knowing that

w=2\pi f

Then

w=12\pi

The model is

\boxed{A(t)=0.5cos(12\pi\cdot t)+4}

where t is expressed in minutes

7 0
3 years ago
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