Answer:
x2=−8(y−2)
Step-by-step explanation:
Parabola is a locus of a point which moves at the same distance from a fixed point called the focus and a given line called the directrix.
Let P(x,y) be the moving point on the parabola with
focus at S(h,k)= S(0,0)
& directrix at y= 4
Now,
|PS| = √(x-h)2 + (y-k)2
|PS| = √(x-0)2 + (y-0)2
|PS| = √ x2 + y2
Let ‘d’ be the distance of the moving point P(x,y) to directrix y- 4=0
- d= |ax +by + c|/ √a2 + b2
- d= |y-4|/ √0 + 1
- d= |y-4| units.
equation of parabola is:
- |PS| = d
- √ x2 + y2 = |y-4|
Squaring on both sides, we get:
- x2 + y2 = (y-4)2
- x2 + y2 = y2 -8y + 16
- x2 = - 8y + 16
- x2 = -8 ( y - 2)
This is the required equation of the parabola with focus at (0,0) and directrix at y= 4.
The value would be $13200 because
1 mile = 5280 inches
5280 times 2 1/2 = 13200
Answer:
UT = 104
∠R = 126°
Step-by-step explanation:
Part 1: Finding UT
The symbols on the triangles indicate that the triangles have the same side lengths.
That means 2x + 84 = 14x - 36
We can find the length of UT by solving for x
2x+84=14x−36
<u>Step 1: Subtract 14x from both sides.</u>
2x + 84 − 14x = 14x − 36 − 14x
−12x + 84 = −36
<u>Step 2: Subtract 84 from both sides.</u>
−12x + 84 − 84 = −36 − 84
−12x = −120
<u>Step 3: Divide both sides by -12.</u>
-12x / -12 = -120 / -12
x = 10
Now we know x=10, we can substitute 10 for x to get UT
UT = 2x + 84
UT = 2(10) + 84
UT = 20 + 84
UT = 104
So the length of UT is 104
Part 2: Finding ∠R
Since we know angle R is equal to angle U, we know
10y - 14 = 5y + 56
We can solve for y to find R
<u>Step 1: Subtract 5y from both sides.</u>
10y − 14 − 5y = 5y + 56 − 5y
5y − 14 = 56
<u>Step 2: Add 14 to both sides.</u>
5y−14+14=56+14
5y=70
<u>Step 3: Divide both sides by 5.</u>
5y/5 = 70/5
y=14
Now that we know y=14, we can substitute that value to find ∠R
∠R = 10y - 14
∠R = 10(14) - 14
∠R = 140 - 14
∠R = 126°
Y + 5 = -8/5(x - 1)
y + 5 =-8/5x + 8/5
y + 25/5= -8/5x + 8/5
y = -8/5x - 17/5
