Answer:
6.75
Step-by-step explanation:
2 crackers=5.50
1 cracker=5.50÷2
=2.25
3 crackers=2.25×3
=6.75
Answer:
The Chi-square test of independence
Step-by-step explanation:
The answer to this question is the Chi-square test of independence because it is what is used to determine the existence of an association between nominal/categorical variables. This test is non parametric in nature and it can also be called the chi square test of association.
The data is tabulated. each row is a representation of the category for one of the variables and each column is for the other variable.
Answer:
The expected number of contracts the sales representative will get this week is 5.22
Step-by-step explanation:
For each client, there are only two possible outcomes. Either there is a sales contract, or there is not. The probability of having a sale contract with each client is independent of other clients. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:

In this problem, we have that:

What is the expected number of contracts the sales representative will get this week?

The expected number of contracts the sales representative will get this week is 5.22
A: Division
you would take the 438/15 to find out how many teams there are
Answer:
Supplementary angles; 148°
Step-by-step explanation:
180° - 32° = 148° (supplementary angles)