Remember, the length of the longest sid must be less than the sum of the other 2 sidess
33 is longest
33<24+8
33<32
false
it would not make a triangle
Solution
Question 1:
- Use of the area of squares to explain the Pythagoras theorem is given below
- The 3 squares given above have dimensions: a, b, and c.
- The areas of the squares are given by:
- The Pythagoras theorem states that:
"The sum of the areas of the smaller squares add up to the area of the biggest square"
Thus, we have:
Question 2:
- We can apply the theorem as follows:
![\begin{gathered} 10^2+24^2=c^2 \\ 100+576=c^2 \\ 676=c^2 \\ \text{Take square root of both sides} \\ \\ c=\sqrt[]{676} \\ c=26 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2010%5E2%2B24%5E2%3Dc%5E2%20%5C%5C%20100%2B576%3Dc%5E2%20%5C%5C%20676%3Dc%5E2%20%5C%5C%20%5Ctext%7BTake%20square%20root%20of%20both%20sides%7D%20%5C%5C%20%20%5C%5C%20c%3D%5Csqrt%5B%5D%7B676%7D%20%5C%5C%20c%3D26%20%5Cend%7Bgathered%7D)
Thus, the value of c is 26
Answer:
B: 22.5 degrees
Step-by-step explanation:
The interior angles of a pentagon add up to 540 degrees
(if you dont believe me you can turn a pentagon into three triangles, 3x180 = 540)
So you have four same angles say measure "x" degrees, and one final one that measures "5x" degrees, so 9x = 540, and x = 60
Unless I read the problem wrong, 60 degrees is the answer which is not an option :P
Edit: Yea I read it wrong, the final angle is 5 times the other four angles COMBINED, so that angle measures "20x" degrees.
The total would be 24x = 540, and so x = 22.5
If one raw contains 3x-2 trees & if the total trees in the rectangle are 24x-16, that means Horizontal Rows x Vertical Rows =Total number of trees:
(3x-2) * Vertical Rows = 24x-16 ===> Vertical Rows =(24x-16) / (3x-2)
Perform the division & you will find Vertical Rows =8
Surface area of the cylinder is 294π in².
Step-by-step explanation:
- Step 1: Surface area of a cylinder = 2πrh + 2πr² Here, r = 7 in, h = 14 in
⇒ Surface Area = 2 × π × 7 × 14 + 2 × π × 7 × 7
= π (196 + 98) = 294π in²
