Based on the given condition, since the rectangle is inscribed in a circle given the length to be 3x, the width can be approximated by taking the right triangle formed by the radius and the w/2, sin 45 = w/2/r, which is equal to w = 2r sin45, therefore the Area of the inscribed rectangle = LxW = (3x)(2rsin45)
Answer:
47.25 ft³
Step-by-step explanation:
The volume of the prism is given by the formula ...
V = Bh . . . . . . . B is the area of the base, h is the height.
The height of the prism is given as 6 ft. The area of the base is the area of the triangular entrance. The formula for that area is ...
A = 1/2bh . . . . . . b is the base, h is the height
Using the given values for the entrance base and height, we get ...
A = 1/2(4.5 ft)(3.5 ft) = 7.875 ft²
Then the volume of the tent is ...
V = (7.875 ft²)(6 ft) = 47.25 ft³
The tent volume is 47.25 cubic feet.
Slope intercept form is: y = mx + b
Isolate the y. First subtract 10x from both sides
10x (-10x) + 2y = 8 (-10x)
2y = -10x + 8
Isolate the y. Divide 2 from both sides and <em>all</em> terms.
(2y)/2 = (-10x + 8)/2
y = -5x + 4
y = -5x + 4 is your slope intercept form answer.
hope this helps
Answer:
3
Step-by-step explanation:
I think it three sometimes it's a trick question
so its not number one or 2 because how are they her children so the answer is 3
